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Yuki888 [10]
2 years ago
6

A solution of saline may contain 1.81 mol of sodium chloride (NaCl). How many sodium atoms are present in the solution?

Chemistry
1 answer:
joja [24]2 years ago
5 0

Answer:

1.09 x 10²⁴ atoms Na

Explanation:

In one mole of NaCl, there is also one mole of Na. To convert between moles and atoms, you need to use Avogadro's number. When writing the conversion, the desired unit (atoms) should be placed in the numerator to allow for the cancellation of units (moles). The final answer should have 3 sig figs to match the given number (1.81 mole).

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

1.81 moles Na           6.022 x 10²³ atoms
---------------------  x  --------------------------------  =  1.09 x 10²⁴ atoms Na
                                       1 mole

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I’m not a 100% shure but I would personally say OIL SPILLS.
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Which compound would most likely turn litmus paper to a red color?
sleet_krkn [62]
Answer D, because it's acid
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3 years ago
PLEASE HELP ME
ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

We were given the following:

Total pressure = 2.45 atm

Pressure of oxygen = 0.65 atm

Pressure of carbon monoxide = x

Pressure of carbon dioxide = 0.65 atm

Therefore:

2.45 = x + 0.65 + 0.65

2.45 = x + 1.3

x = 2.45 - 1.3

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6 0
3 years ago
A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant?
KengaRu [80]

Answer:

d. Copper (II) sulfate

Explanation:

Given data:

Mass of Al = 1.25 g

Mass of CuSO₄ = 3.28 g

What is limiting reactant = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂ (SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 1.25 g/ 27 g/mol

Number of moles = 0.05 mol

Number of moles of CuSO₄:

Number of moles = mass/molar mass

Number of moles = 3.28 g/ 159.6 g/mol

Number of moles = 0.02 mol

now we will compare the moles of reactant with product.

               Al           :           Al₂ (SO₄)₃

                 2          :             1

               0.05       :          1/2×0.05=0.025 mol

                Al           :            Cu

                 2            :              3

               0.05         :            3/2×0.05 = 0.075 mol

         CuSO₄           :           Al₂ (SO₄)₃

                3             :             1

               0.02         :          1/3×0.02=0.007 mol

         CuSO₄           :            Cu

               3               :              3

               0.02         :              0.02

Less number of moles of reactants are produced by CuSO₄ thus it will act as limiting reactant.

4 0
3 years ago
What happens ????????
ivolga24 [154]
Correct me if I wrong but I think it's "c"
5 0
3 years ago
Read 2 more answers
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