Answer:
A.The potential energy increases because the charges have a greater repulsion.
Explanation: Thanks to Mwilliams55513 for the help :}
Answer : The maximum amount of nickel(II) cyanide is 
Explanation :
The solubility equilibrium reaction will be:

Initial conc. 0.220 0
At eqm. (0.220+s) 2s
The expression for solubility constant for this reaction will be,
![K_{sp}=[Ni^{2+}][CN^-]^2](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BNi%5E%7B2%2B%7D%5D%5BCN%5E-%5D%5E2)
Now put all the given values in this expression, we get:


Therefore, the maximum amount of nickel(II) cyanide is 
Answer:
The pH of the sample is 3,4.
Explanation:
We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:
pOH= -log (OH-)=10,60
pH + pOH = 14
pH + 10,60 = 14
pH=14 -10,60
<em>pH=3,4</em>
Explanation:
Br2 + S2O32- + 5H2O –> 2Br- + 2SO4 + 10H+ + 6e