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2 years ago

15

The midpoint of UV is (5, -11). The coordinates of one endpoint are U(3,5). Find the coordinates of endpoint V.

1 answer:

raketka [301]2 years ago

7 0

Using the midpoint formula of the coordinates we get V has x axis of 7 and y axis of -27.

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The diagram shows several planes, lines, and points. Vertical plane P intersects horizontal plane R at line f. Vertical plane T

Rudiy27

Please mark brainliest

Answer:

Line H has points on planes R, T, P

Step-by-step explanation:

I just took the test on Edgenuity 2020. Good luck

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2 years ago

The town park is a rectangular strip of land with a width of 1/2 miles and an area of 1/8 square miles. How long is the town par

ASHA 777 [7]

I think it is A 1/16

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2 years ago

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Polynomial function in standard form with zeros 5,-4,1

Oksanka [162]

Answer:

$\boxed{\sf \ \ \ x^3-2x^2-19x+20 \ \ \ }$

Step-by-step explanation:

hello,

by definition we can write

$(x-5)(x+4)(x-1)$

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

$(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20$

hope this helps

5 0

3 years ago

All of the points in the graph are on the same line.<br><br> Find the slope of the line.

geniusboy [140]

Answer:

The slope of the line is $\frac{1}{2}$ .

-

Step-by-step explanation:

☆Remember:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

☆Just plug it in with 2 sets of coordinate points.

$m = \frac{7 - 3}{9 - 1} = \frac{4}{8} = \frac{1}{2}$

8 0

3 years ago

Complete the square to make a perfect square trinomial. Then, write the result as a binomial squared. q2+11q

Sedbober [7]

Answer:

$(q+\frac{11}{2})^2-\frac{121}{4}$

Step-by-step explanation:

We have been given an expression $q^2+11q$ . We are asked to complete the square to make a perfect square trinomial. Then, write the result as a binomial squared.

We know that a perfect square trinomial is in form $a^2+2ab+b^2$ .

To convert our given expression into perfect square trinomial, we need to add and subtract $(\frac{b}{2})^2$ from our given expression.

We can see that value of b is 11, so we need to add and subtract $(\frac{11}{2})^2$ to our expression as:

$q^2+11q+(\frac{11}{2})^2-(\frac{11}{2})^2$

Upon comparing our expression with $(a+b)^2=a^2+2ab+b^2$ , we can see that $a=q$ , $2ab=11q$ and $b=\frac{11}{2}$ .

Upon simplifying our expression, we will get:

$(q+\frac{11}{2})^2-\frac{11^2}{2^2}$

$(q+\frac{11}{2})^2-\frac{121}{4}$

Therefore, our perfect square would be $(q+\frac{11}{2})^2-\frac{121}{4}$ .

8 0

2 years ago

Read 2 more answers