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BlackZzzverrR [31]
2 years ago
12

Can you answer one of the questions

Physics
1 answer:
bagirrra123 [75]2 years ago
4 0

Answer:

2.e

3.b

4.c conduction needs friction

5.a

1, d

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B. The silica cylinder of a radiant wall heater is 0.6 m long
SIZIF [17.4K]

So,  If the silica cyliner of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K

To estimate the operating temperature of the radiant wall heater, we need to use the equation for power radiated by the radiant wall heater.

<h3>Power radiated by the radiant wall heater</h3>

The power radiated by the radiant wall heater is given by P = εσAT⁴ where

  • ε = emissivity = 1 (since we are not given),
  • σ = Stefan-Boltzmann constant = 6 × 10⁻⁸ W/m²-K⁴,
  • A = surface area of cylindrical wall heater = 2πrh where
  • r = radius of wall heater = 6 mm = 6 × 10⁻³ m and
  • h = length of heater = 0.6 m, and
  • T = temperature of heater

Since P = εσAT⁴

P = εσ(2πrh)T⁴

Making T subject of the formula, we have

<h3>Temperature of heater</h3>

T = ⁴√[P/εσ(2πrh)]

Since P = 1.5 kW = 1.5 × 10³ W

Substituting the values of the variables into the equation, we have

T = ⁴√[P/εσ(2πrh)]

T = ⁴√[1.5 × 10³ W/(1 × 6 × 10⁻⁸ W/m²-K⁴ × 2π × 6 × 10⁻³ m × 0.6 m)]

T = ⁴√[1.5 × 10³ W/(43.2π  × 10⁻¹¹ W/K⁴)]

T = ⁴√[1.5 × 10³ W/135.72  × 10⁻¹¹ W/K⁴)]

T = ⁴√[0.01105 × 10¹⁴ K⁴)]

T = ⁴√[1.105 × 10¹² K⁴)]

T = 1.0253 × 10³ K

T = 1025.3 K

So, If the silica cylinder of the radiant wall heater is rated at 1.5 kw its temperature when operating is 1025.3 K

Learn more about temperature of radiant wall heater here:

brainly.com/question/14548124

6 0
2 years ago
What is the KE of a bicycle with a mass of 41kg traveling at a velocity of 8 m/s ?
zhuklara [117]

Answer:

What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Physics ... K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

1 answer  

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

Explanation:

K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

3 0
2 years ago
A box of mass 64 kg is at rest on a horizontal frictionless surface. A constant horizontal force F~ then acts on the box and acc
iren2701 [21]

Answer:

The correct answer is;

The magnitude of the force is 35.12 N

Explanation:

To solve the question, we note that the friction is zero and the force causes motion of a stationary mass

One of the equations of motion is required such as

v² = u² + 2× a× s

Where

v = Final velocity = 5.93 m/s

u = Initial velocity = 0 m/s , object at rest

a = acceleration

s = distance moved = 32 meters

But v = Distance/Time = 32 m /5.4 s = 5.93 m/s

Therefore

5.93² = 2×a×32

or a = 35.12/ 64 = 0.55 m/s²

Therefore Force F = Mass m × Acceleration a

Where mass m = 64 kg

Therefore F = 64 kg×0.55 m/s² = 35.12 N

3 0
3 years ago
A solid sphere of radius A has auniform magnatization
worty [1.4K]

Answers and Explanation:

The step by step explanation is clearly screenshot in the two attachments below for easy understanding.

NOTE:

A uniform charged solid sphere of radius R carries a total charge Q, it therefore has its charge density as Q/(4/3ΠR³). And to find magnetic moment of a sphere, the sphere has to be divided into infinitesimal charges.

Magnetic Dipole Moment of the sphere would be given as 1/5QwR²z

(Check attachments below for clarity)

8 0
3 years ago
The primary coil of a transformer is connected to a 120 v wall outlet. the secondary coil is connected to a lamp that dissipates
Lyrx [107]

Energy/power is not gained or lost going through a (ideal) transformer.

So the transformer in this problem really doesn't matter.  If the lamp is using energy at the rate of 60 watts, then the whole contraption is getting 60 watts of power from the wall outlet.

Power = (voltage) x (current)

60 watts = (120 v) x (current)

Current = (60 watts) / (120 v)

<em>Current = 0.5 Ampere</em>

5 0
3 years ago
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