Answer:
3.10 mole of C3H8O change in entropy is 89.54 J/K
Explanation:
Given data
mole = 3.10 moles
temperature = -89.5∘C = -89 + 273 = 183.5 K
ΔH∘fus = 5.37 kJ/mol = 5.3 ×10^3 J/mol
to find out
change in entropy
solution
we know change in entropy is ΔH∘fus / melting point
put these value so we get change in entropy that is
change in entropy 5.3 ×10^3 / 183.5
change in entropy is 28.88 J/mol-K
so we say 1 mole of C3H8O change in entropy is 28.88 J/mol-K
and for the 3.10 mole of C3H8O change in entropy is 3.10 ×28.88 J/K
3.10 mole of C3H8O change in entropy is 89.54 J/K
Answer: [B]: The letter, "<em /> I " ; for current; in units of "Amps" .
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Answer:
The height is : 60.025 m
Explanation:
The flowerpot falls off the balcony with zero launch angle
Given the time of fright as 3.5 s then ;
The formula to apply is ;
3.5²= 2H/9.8
12.25 =2H/9.8
12.25 * 9.8 = 2H
120.05 = 2H
120.05/2 = H
60.025 =H
If the mass of the sun is 1x, at least one planet will fall into the habitable zone. if I place a planet in orbits 2, 6, and 75, and all planets will orbit the sun successfully.
If the mass of the sun is 2x, at least one planet will fall into the habitable zone. if I place a planet in orbits 84, 1, and 5, and all planets will orbit the sun successfully.
If the mass of the sun is 3x, at least one planet will fall into the habitable zone if I place a planet in orbits 672, and 7 and all planets will orbit the sun successfully.
Answer:
Re=160ohm
Explanation:
Step#1
Rt=R1+R2 ( because both are in series)
Rt=(100+220 ) ohm
Rt=320 ohm
Step#2
Rt and R3 are parallel so,
Re= (Rt× R3) ÷ (Rt+R3)
Re= (320×320)÷( 320+320)
Re = 102,400÷ 640
Re=160ohm
