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3 years ago

How are defenders on a baseball team positioned ?

Physics

2 answers:

Ulleksa [173]3 years ago

8 0

Answer:

1 (pitcher), 2 (catcher), 3 (first baseman), 4 (second baseman), 5 (third baseman), 6 (shortstop), 7 (left fielder) 8 (center fielder), and 9 (right fielder)

Explanation:

There are nine fielding positions in baseball. Each position conventionally has an associated number, for use in scorekeeping by the official score

Gwar [14]3 years ago

3 0

There’s 3 outfield , and the rest are infield !

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[3 points] Question: Consider a pendulum made from a uniform, solid rod of mass M and length L attached to a hoop of mass M and

aliina [53]

Answer:

I= $\frac{4}{3}ML^2+2MR^2+2MRL$

Explanation:

We are given that

Mass of rod=M

Length of rod=L

Mass of hoop=M

Radius of hoop=R

We have to find the moment of inertia I of the pendulum about pivot depicted at the left end of the slid rod.

Moment of inertia of rod about center of mass= $\frac{1}{12}ML^2$

Moment of inertia of hoop about center of mass= $MR^2$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{1}{12}ML^2+M(\frac{L}{2})^2+MR^2+M(L+R)^2$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{1}{12}ML^2+\frac{1}{4}ML^2+MR^2+MR^2+ML^2+2MRL$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{1+3+12}{12}ML^2+2MR^2+2MLR$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{16}{12}ML^2+2MR^2+2MRL$

Moment of inertia of the pendulum about the pivot left end,I= $\frac{4}{3}ML^2+2MR^2+2MRL$

8 0

4 years ago

Read 2 more answers

When a marble rolls down a slope which forces acts on it

Tema [17]

Answer:

What forces act on a marble rolling down a ramp?

Answer: Gravity acts vertically downward. A normal force acts from the ruler toward the marble/ball in a direction that is perpendicular to the plane of the ruler. Friction acts in the direction opposite to which the marble/ball is moving. ... Friction slows down the marble/ball.

4 0

4 years ago

Finally, the switch on the electromagnet is reopened. The magnitude of the external magnetic flux through the wire loop ______ (

Natali5045456 [20]

C. Is my best guess!

5 0

3 years ago

PLEASE HELP !!

LenKa [72]

Explanation:

It is given that

The kinetic energy of Mr. Thomson’s prius, K = 641300 J

He is moving with a velocity, v = 22 m/s

It is required to find the mass of Mr. Thomson’s prius.

Due to his motion, a kinetic energy will possess by him. The mathematical form of kinetic energy is given by :

$K=\dfrac{1}{2}mv^2$

Solving for m

$m=\dfrac{2K}{v^2}$

Plugging all the values, we get :

$m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 641300}{(22)^2}\\\\m=2650\ kg$

So, the mass of Mr. Thomson’s prius is 2650 kg.

8 0

4 years ago

A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreci

Mars2501 [29]

<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)</span>

8 0

4 years ago