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pochemuha
2 years ago
14

What is the optimum pH of formic acid-formate buffer? (The pK, of formic acid is 3.75.)

Chemistry
1 answer:
uysha [10]2 years ago
3 0

The optimum pH of formic acid - formate buffer is 3.75

<h3>What is Buffer ? </h3>

A substance or a solution which resists any changes in pH, when acid or alkali is added to it.

pH = pKa + log[base] / [acid]

Considering equimolar concentration of acid and base

pH = 3.75 + log(x)/(x)

pH = 3.75 + log (1)

pH = 3.75 + 0

pH = 3.75

Hence,

The optimum pH of formic acid - formate buffer is 3.75

Learn more about pH here ;

brainly.com/question/491373

#SPJ1

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6 0
3 years ago
If a piece of cadmium with a mass of 37.60 g and a temperature of 100.0 oC is dropped into 25.00 cc of water at 23.0 oC, what wi
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Answer:

T_{eq}=28.9\°C

Explanation:

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In this case, since it is observed that hot cadmium is placed in cold water, we can infer that the heat released due to the cooling of cadmium is gained by the water and therefore we can write:

Q_{Cd}+Q_{W}=0

Thus, we insert mass, specific heat and temperatures to obtain:

m_{Cd}C_{Cd}(T_{eq}-T_{Cd})+m_{W}C_{W}(T_{eq}-T_{W})=0

In such a way, since the specific heat of cadmium and water are respectively 0.232 and 4.184 J/(g °C), we can solve for the equilibrium temperature (the final one) as shown below:

T_{eq}=\frac{m_{Cd}C_{Cd}T_{Cd}+m_{W}C_{W}T_{W}}{m_{Cd}C_{Cd}+m_{W}C_{W}}

Now, we plug in to obtain:

T_{eq}=\frac{37.60g*0.232\frac{J}{g\°C}*100.00\°C+25.00g*4.184\frac{J}{g\°C}*23.0\°C}{37.60g*0.232\frac{J}{g\°C}+25.00g*4.184\frac{J}{g\°C}}\\\\T_{eq}=28.9\°C

NOTE: since the density of water is 1g/cc, we infer that 25.00 cc equals 25.00 g.

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6 0
3 years ago
(a)-Use Lewis symbol store present there action that occurs between Ca and F atoms. (b)-What is the chemical formula of the most
Charra [1.4K]

Answer:

(a) The Lewis structure is shown in the image below.

(b) CaF_2

(c) Calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond.

(d) Calcium atom loses electrons.

Explanation:

Calcium is the element of second group and forth period. The electronic configuration of Calcium is - 2, 8, 8, 2 or 1s^22s^22p^63s^23p^64s^2

There are 2 valence electrons of Calcium.

Fluorine is the element of group 17 and second period. The electronic configuration of the element fluorine is - 2, 7 or  1s^22s^22p^5

There is 1 valence electron of fluorine.

The Lewis structure is drawn in such a way that the octet of each atom is complete.  

Thus, calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond. This is done in order that the octet of the atoms are complete and they become stable.

Thus, the formula of calcium chloride is CaF_2.

<u>(a) The Lewis structure is shown in the image below.</u>

<u>(b) CaF_2</u>

<u>(c) Calcium loses 2 electrons to 2 atoms of fluorine and these 2 atoms of fluorine accepts each electron to form ionic bond.</u>

<u>(d) Calcium atom loses electrons.</u>

5 0
3 years ago
When 1 carbon atom combines with 2 oxygen atoms, the resulting substance is called a​
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Answer:

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7 0
3 years ago
Help me with this questions please
mina [271]
I will figure out the answer and i will letu know what else do u want to talk about .
do u want to talk about periods
8 0
3 years ago
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