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Triss [41]
3 years ago
11

What is the decay mode of radium-226?

Chemistry
1 answer:
inn [45]3 years ago
6 0

Answer:

Radium-226 is a radioactive decay product in the uranium-238 decay series and is the precursor of radon-222. Radium-228 is a radioactive decay product in the thorium-232 decay series. Both isotopes give rise to many additional short-lived radionuclides, resulting in a wide spectrum of alpha, beta and gamma radiations.

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The pressure of 1 mol of gas is decreased to 0.5 atm at 273 K. What happens to the molar volume of the gas under these condition
m_a_m_a [10]

Answer : The molar volume of the gas will be, 44.82 L

Solution :

Using ideal gas equation,

PV=nRT

where,

n = number of moles of gas  = 1 mole

P = pressure of the gas = 0.5 atm

T = temperature of the gas = 273 K

R = gas constant = 0.0821 Latm/moleK

V = volume of the gas.

Now put all the given values in the above equation, we get the molar volume of the gas.

(0.5atm)\times V=(1mole)\times (0.0821Latm/moleK)\times (273K)

V=44.82L

Therefore, the molar volume of the gas will be, 44.82 L

6 0
3 years ago
Is bread a molecule or a compound?
Morgarella [4.7K]

it's molecule.......

3 0
2 years ago
Read 2 more answers
Need help asap please!
Andrei [34K]

Answer:

B

Explanation:

because polarity of the water molecules is due to the B. deflection of the hydrogen atoms by the lone pair of electrons.

4 0
2 years ago
The characteristic bright-line spectrum of an atom is produced when
Inessa05 [86]

Bright Line Emission Spectrum: As the excited electron returns to ground state (it's lower energy level) the energy it originally absorbed is released as discrete lines of light.

8 0
3 years ago
Green plants use light from the Sun to drive photosynthesis, a chemical reaction in which liquid water and carbon dioxide gas fo
Luda [366]

Answer:

0.800 mol of O2

Explanation:

<em>Calculate the moles of oxygen produced by the reaction of 0.800mol of carbon dioxide.</em>

The balanced equation for the reaction is given as;

6CO2 + 6H2O → C6H12O6 + 6O2  

From the reaction;

6 mol of CO2 produces 6 mol of O2

0.0800 mol of CO2 would produce x mol of O2

6 = 6

0.0800 = x

Solving for x;

x = 6 * 0.800 / 6

x = 0.800 mol

5 0
2 years ago
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