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ipn [44]
2 years ago
15

1. Huntington’s disease is a dominant allele (not sex linked) that usually does not manifest itself until after age thirty- five

. Individual who have the disease are almost always heterozygous. As a genetics counselor, you are visited by a 23-year-old woman. Her mother has Huntigton’s, but her father is normal. Use alphabets when required.
a. What is the genotype of the mother?

b. What is the genotype of the father?

c. What is the probability that this woman will develop Huntington’s disease as she grows older ?


WHO KNOWS HOW TO DO THIS
Chemistry
1 answer:
masya89 [10]2 years ago
4 0

Answer:

a the mother is heterozygous so Aa

b would be aa

c. 50% as she could either get the dominant allele from her mother or not it is a coin flip

Explanation:for c the best way to do that one is to draw a punnitt square

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Out of the following choices, the one that shows a periodic pattern is "the mother takes her medication everyday at 7." 
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PLEASE HELP!
fgiga [73]
150/30 = 5
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Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
4 0
3 years ago
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When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II)
lesya692 [45]

Answer: The mass of lead deposited on the cathode of the battery is 1.523 g.

Explanation:

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Time = 23.0 sec

Formula used to calculate charge is as follows.

Q = I \times t

where,

Q = charge

I = current

t = time

Substitute the values into above formula as follows.

Q = I \times t\\= 62.0 A \times 23.0 sec\\= 1426 C

It is known that 1 mole of a substance tends to deposit a charge of 96500 C. Therefore, number of moles obtained by 1426 C of charge is as follows.

Moles = \frac{1426 C}{96500 C/mol}\\= 0.0147 mol

The oxidation state of Pb in PbSO_{4} is 2. So, moles deposited by Pb is as follows.

Moles of Pb = \frac{0.0147}{2}\\= 0.00735 mol

It is known that molar mass of lead (Pb) is 207.2 g/mol. Now, mass of lead is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\ 0.00735 = \frac{mass}{207.2 g/mol}\\mass = 1.523 g

Thus, we can conclude that the mass of lead deposited on the cathode of the battery is 1.523 g.

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m_a_m_a [10]

Answer:

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