Ask question

Ask question

All categories

2 years ago

13

What happens to a 8 L volume of gas as you love a pressure of 3 atm to 4 atm? Use the correct gas law to determine the new volum

e

1 answer:

bezimeni [28]2 years ago

7 0

Assuming pressure is held constant,

$\frac{8}{3}=\frac{V_{2}}{4}\\\\V_{2}=4\left(\frac{8}{3} \right) \approx \boxed{10.7 \text{ L}}$

You might be interested in

A trophic level is a number that tells you the position an organism occupies in a food chain or food pyramid.

svet-max [94.6K]

Answer:

true

Explanation:

8 0

3 years ago

When u look at the sun through a filtered telescope, the visible portion of the sun appears blotchy

VashaNatasha [74]

What is the question?

7 0

3 years ago

Read 2 more answers

The equilibrium constant for the reaction

Hitman42 [59]

The question is incomplete, here is the complete question:

The equilibrium constant for the reaction

N₂O₄(g)⇌2NO₂ at 2°C is Kc = 2.0

If each yellow sphere represents 1 mol of N₂O₄(g) and each gray sphere 1 mol of NO₂ which of the following 1.0 L containers represents the equilibrium mixture at 2°C?

The image is attached below.

<u>Answer:</u> The system which represents the equilibrium having value of $K_c=2.0$ is system (b)

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_{c}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical equation:

$N_2O_4(g)\rightleftharpoons 2NO_2$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$ .......(1)

We are given:

Volume of the container = 1.0 L

Value of $K_c$ = 2.0

Molarity of the substance is calculated by using the equation:

$\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume}}$

For the given images:

<u>For a:</u>

Number of Gray spheres = 8 moles

Number of yellow spheres = 4 moles

Putting values in expression 1, we get:

$K_c=\frac{(8/1)^2}{(4/1)}\\\\K_c=16$

<u>For b:</u>

Number of Gray spheres = 4 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

$K_c=\frac{(4/1)^2}{(8/1)}\\\\K_c=2$

<u>For c:</u>

Number of Gray spheres = 6 moles

Number of yellow spheres = 6 moles

Putting values in expression 1, we get:

$K_c=\frac{(6/1)^2}{(6/1)}\\\\K_c=6$

<u>For d:</u>

Number of Gray spheres = 2 moles

Number of yellow spheres = 8 moles

Putting values in expression 1, we get:

$K_c=\frac{(2/1)^2}{(8/1)}\\\\K_c=\frac{1}{2}$

Hence, the system which represents the equilibrium having value of $K_c=2.0$ is system (b)

3 0

3 years ago

Lorelai discovers a compound that is 64.8 g C, 13.62 g H, and 21.58 g O. What is the empirical formula of Lorelai's compound

jenyasd209 [6]

The empirical formula of Lorelai's compound is C₄H₁₀O

<h3>Data obtained from the question</h3>

C = 64.8 g
H = 13.62 g
O = 21.58 g
Empirical formula =?

<h3>How to determine the empirical formula</h3>

Divide by their molar mass

C = 64.8 / 12 = 5.4

H = 13.62 / 1 = 13.62

O = 21.58 / 16 = 1.35

Divide by the smallest

C = 5.4 / 1.35 = 4

H = 13.62 / 1.35 = 10

O = 1.35 / 1.35 = 1

Thus, the empirical formula of the compound is C₄H₁₀O

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

7 0

2 years ago

A student shines a flashlight on the lens. Which best describes what happens when light rays exit the lens?

zhannawk [14.2K]

The flashlight's beam will all be refracted towards a central axis. But, this is still dependent on the type of lens that is used for the said activity. The speed of light will vary depending whether the lens is a concave or a convex lens. The exit point of the light will always head towards the central axis.

7 0

3 years ago

Read 2 more answers