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pshichka [43]
2 years ago
7

What thorium has 90 protons and 137 neutrons?

Chemistry
2 answers:
faltersainse [42]2 years ago
6 0

Answer : The representation of thorium isotope is ^{227}_{90}Th

Explanation :

Isotope : It is defined as the element that have the same number of protons but have the different number of neutrons of each of the atom.

Atomic number is defined as the number of protons or number of electrons.

Atomic number = number of protons = number of electrons

Mass number is defined as the sum of number of protons and number of neutrons.

Number of neutrons = Mass number - Number of protons

Isotope notation : It is also called as nuclear notation. In isotopic notation we can easily determine an isotope's mass number, atomic number, the number of neutrons and protons in the nucleus.

The general isotopic representation of an atom is:

_Z^A\textrm{X}

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

As we given:

Number of protons = 90

Number of neutrons = 137

Atomic number = number of protons = 90

Mass number = Number of neutrons + Number of protons

Mass number = 137 + 90

Mass number = 227

The symbol of thorium = Th

Thus, the representation of thorium isotope is ^{227}_{90}Th

Ket [755]2 years ago
5 0
<span> a silvery white metal which maintains its luster for several months unless it </span>is<span> exposed to oxygen and then it eventually turns black. </span>
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Varvara68 [4.7K]

Answer: 31.8 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al_2O_3=\frac{60.0g}{102g/mol}=0.59moles

\text{Moles of} C=\frac{30.0g}{12g/mol}=2.5moles

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According to stoichiometry :

1 mole of Al_2O_3 require 3 moles of C

Thus 0.59 moles of Al_2O_3 will require=\frac{3}{1}\times 0.59=1.77moles  of C

Thus Al_2O_3 is the limiting reagent as it limits the formation of product and C is the excess reagent as it is present in more amount than required.

As 1 mole of Al_2O_3 give = 2 moles of Al

Thus 0.59 moles of Al_2O_3 give =\frac{2}{1}\times 0.59=1.18moles  of Al

Mass of Al=moles\times {\text {Molar mass}}=1.18moles\times 27g/mol=31.8g

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5 0
3 years ago
4. If they..................me a question d have answered it.(ask/asked/had asked)​
LekaFEV [45]

Answer:

had asked

Explanation:

If they had asked me a question, I would have answered it.

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Explanation:

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Explanation:

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