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jeyben [28]
2 years ago
7

M

Mathematics
2 answers:
Alona [7]2 years ago
6 0

Based on the coordinates of triangle RST, we can infer that triangle RST is <u>not a right-angled triangle. </u>

<h3>Is triangle RST a right-angled triangle?</h3>

For this to be a right-angled triangle, the Pythagoras theorem has to apply where:

Largest side² = Side A² + Side B²

Lengths of the triangle:

RS² = (4 - 2)² + (4 - 3)²

= 5

ST² = (5 - 4)² + (0 - 9)²

= 17

TR² = (2 - 5)² + (3 - 0)²

= 18

We can see that:

18 ≠ 17 + 5

This is therefore not a right-angled triangle.

Find out more on the Pythagoras theorem at brainly.com/question/343682.

#SPJ9

AlekseyPX2 years ago
5 0

Step-by-step explanation:

given the point 23 44 and 50. To determine if the right triangle, you want to find the slopes, the slope of rs the slope of S. T. And the slope of R. T. The slope is always the difference of your Y coordinate. So if it's R. S would be four minus 3/4 minus two. Difference of the Y coordinates Over the difference of the x coordinates, that would be 1/2 the scope of S. T. Using points S and T Would be 0 -4/5 -4. That's negative for over one or -4. In the soap of R. T would be zero minus 3/5 minus two, which would be negative 3/3, Which is positive one. So since we don't have any slopes that are opposite reciprocal als, then there are no perpendicular lines, so not a right triangle. Okay, no perpendicular lines.

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<u>Algebra I</u>

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<u>Calculus</u>

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Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

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