Answer:
2HNO3 + Ca(OH)2 ===> Ca(NO3)2 + 2H2O
Explanation:
This a neutralisation reaction. The first thing to note is that this type of reaction forms salt and water.
Note that the formula of water is H2O. So write this at the right hand side.
==> H2O
Next note that the salt should contain the acid radical (NO3) and the metallic part of the base (Ca) written well following the rule for writing chemical equation; thus
==> Ca(NO3)2 + H2O
The next step is to write the reactants at the right hand side of the equation;
HNO3 + Ca(OH)2 ==> Ca(NO3)2 + H2O
The final step is to count the number of atoms in each side of the equation to make sure they are equal and balanced.
In the above equation, H atoms are three at the left hand side add 2 to to H- containig compound on both side as to balance up. Thus
2HNO3 + Ca(OH)2 ===> Ca(NO3)2 + 2H2O
The equation 2HNO3 + Ca(OH)2 ===> Ca(NO3)2 + 2H2O is balance.
The amount of sugar is 2621 mg
Why?
The complete question is:
A 12.630 g milk chocolate bar is found to contain 8.315 g of sugar.
Part B. What will be the amount of sugar in milligrams if the size of the milk chocolate bar is reduced from 12.630 g to 4.000 g ?
To find the answer we have to determine first the amount of sugar in milligrams per gram of chocolate bar. We can find that by applying the following conversion factor:
Now, we have to determine the amount of sugar in milligrams if we had a chocolate bar with 4.000 g:
Have a nice day!
Answer: Scientists are working on nuclear fusion process. Nuclear fusion is the process in which two atomic nuclei combine to form another nuclei. In the process either energy is absorbed or released due to the difference in the mass of reactants and products.
Explanation:
Answer:
1) 0 N
2) 8 N
Explanation:
The net force is the sum of all of the forces acting on the object.
For question 1, we can see that there is a force of 5 N acting to the right and 5 N acting to the left. If we define the right to be positive and the left to be negative, then the net force equals:
Fnet = 5N - 5N = 0 N
Therefore, the net force in question 1 is 0 N.
For question 2, the process is very similar. We want to find the sum of the forces acting on the object. In this case, there are forces of 3 N and 5 N acting to the right.
Fnet = 3 N + 5 N = 8 N
Therefore, the net force in question 2 is 8 N.
Hope this helps!
