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Gnom [1K]
2 years ago
9

A mixture of NaCl and CuCO3 was dissolved in water and the resulting slurry was filtered in to a beaker. The beaker and the filt

er paper were dried and weighed.
Mass of container: 54.558g
Mass of container and mixture: 56.779g
Mass of filter paper: 1.176g
Mass of filter paper and residue: 2.656g
Mass of beaker: 77.575g
Mass of beaker and dried residue: 78.875g

Mass of mixture =
Mass of NaCl =
%NaCl (w/w) =
Mass of CuCO3 =
% (w/w) CuCO3 =

Do the percentages add up to 100% in this example? Why or why not? What do you think happened?
Chemistry
1 answer:
Firdavs [7]2 years ago
6 0

The percentage adds up to 100%.

<h3>Percentages</h3>

Mass of mixture = mass of container+mixture - mass of container = 56.779 - 54.558 = 2.221 g

CuCO3 is insoluble in water. Thus:

Mass of CuCO3 = mass of beaker and residue - mass of beaker = 78.875 - 77.575 = 1.300 g

Mass of NaCl = mass of mixture - mass of CuCO3 = 2.221 - 1.300 = 0.921 g

%NaCl (w/w) = weight of NaCl/weight of mixture = 10.921/2.221 = 41.468%

% (w/w) CuCO3 = weight of CuCO3/weight of mixture = 1.300/2.221 = 58.532%

Addition of percentages = 41.468 + 58.532 = 100%

More on percentages can be found here: brainly.com/question/24159063

#SPJ1

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What does Q=mcdeltaT stand for ?
AVprozaik [17]
Its a formula relating to specific heat capacity

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4 0
2 years ago
Consider the double replacement reaction given below: HgNO3(aq) + KBr(aq) → HgBr (??) + KNO3(??)The state of matter for HgBr wou
Andreas93 [3]

Answer: The state of maater for HgBr is solid.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.  

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7 0
2 years ago
Acidic solutions contain high concentrations of
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6 0
3 years ago
How many moles are in 39.5 grams of Lithium?
Blizzard [7]

Answer:

185.05 g.

Explanation

Firstly, It is considered as a stichiometry problem.

From the balanced equation: 2LiCl → 2Li + Cl₂

It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.

We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.

n = (30.3 g) / (6.941 g/mole) = 4.365 moles.

Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.

Using cross multiplication:

2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.

??? moles of LiCl → 4.365  moles of Li.

The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.

Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).

Molar mass of LiCl = 42.394 g/mole.

mass = n x molar mass = (4.365 x 42.394) = 185.05 g.

7 0
2 years ago
Read 2 more answers
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