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2 years ago

How to know if a single replacement reaction will occur

Chemistry

1 answer:

Lerok [7]2 years ago

3 0

Answer:

To determine whether a given single replacement will occur, you must use an “Activity Series” table. If the metal or the halogen is above the element it will replace based on the activity series, a single displacement reaction will occur. The video below summarizes an experiment conducted to compare the activities of three metals ( Mg, Cu and Zn ).

Explanation:

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Suppose you were to read about a scientific statement based on data from hundreds of years of research and observation that appl

Dominik [7]

Answer:

theory

Explanation:

A theory has been tested and proven several times and oftentimes has a large amount of information, research, and evidence standing behind it.

Hope this helps! :)

5 0

3 years ago

For each (P, V) pair, type the pressure in the x-column and the volume in the y-column. Then click “Resize window to fit data.”

qwelly [4]

Answer:

V= 51.4 P^= -0.999

the second one is: an inverse proportion

Explanation:

Just did it on Edg

7 0

3 years ago

Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I

Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

At t = 0 0.044M 0.044M 0.177M

At $t=t_{eq}$ (0.044-x)M (0.044-x)M (0.177+x)M

The expression for $K_c$ for the given reaction follows:

$K_c=\frac{[HI]^2}{[H_2]\times [I_2]}$

We are given:

$K_c=52$

Putting values in above equation, we get:

$52=\frac{(0.177+x)^2}{(0.044-x)^2}$

$x=0.0171M$

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0

2 years ago

A company is testing drinking water and wants to ensure that ca content is below 155 ppm. What is the maximum amount of Ca that

BabaBlast [244]

Answer:

138 mg

Explanation:

A company is testing drinking water and wants to ensure that Ca content is below 155 ppm (= 155 mg/kg), that is, <em>155 milligrams of calcium per kilogram of drinking water</em>. We need to find the maximum amount of calcium in 890 g of drinking water.

Step 1: Convert the mass of drinking water to kilograms.

We will use the relation 1 kg = 1000 g.

$890g \times \frac{1kg}{1000g} =0.890kg$