How many grams of
2 answers:
The answer is 82.5 g P2O3
you can use stoichiometry to solve for this problem. you’re given 2.25 mol H2O and when you look at your chemical reaction, you can see there’s 3 moles of H2O (look at the coefficients) and do the mole ratio. so in the chemical reaction, there’s 1 mol P2O3 and 3 mol H2O. you get your moles with that and since you need it in grams, you need to convert it using the P2O3 molar mass.
you can use stoichiometry to solve for this problem. you’re given 2.25 mol H2O and when you look at your chemical reaction, you can see there’s 3 moles of H2O (look at the coefficients) and do the mole ratio. so in the chemical reaction, there’s 1 mol P2O3 and 3 mol H2O. you get your moles with that and since you need it in grams, you need to convert it using the P2O3 molar mass.
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Answer:
9.79740949850 moles
Explanation:
- 1 mole = Avogardo's Number <<6.022 E 23 <<particles, atoms, etc.>>
- This problem can be solved using dimensional analysis by multiplying atoms (5.9E24 atoms) by (1) mole and then dividing the number by Avogardo's number (6.022 E 23 atoms).
- Note: E = * 10
Side Note: Please let me know if you need any clarifications about this!
Answer:
0.558mole of SO₃
Explanation:
Given parameters:
Molar mass of SO₃ = 80.0632g/mol
Mass of S = 17.9g
Molar mass of S = 32.065g/mol
Number of moles of O₂ = 0.157mole
Molar mass of O₂ = 31.9988g/mol
Unknown:
Maximum amount of SO₃
Solution
We need to write the proper reaction equation.
2S + 3O₂ → 2SO₃
We should bear in mind that the extent of this reaction relies on the reactant that is in short supply i.e limiting reagent. Here the limiting reagent is the Sulfur, S. The oxygen gas would be in excess since it is readily availbale.
So we simply compare the molar relationship between sulfur and product formed to solve the problem:
First, find the number of moles of Sulfur, S:
Number of moles of S =
Number of moles of S = = 0.558mole
Now to find the maximum amount of SO₃ formed, compare the moles of reactant to the product:
2 mole of Sulfur produced 2 mole of SO₃
Therefore; 0.558mole of sulfur will produce 0.558mole of SO₃