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adelina 88 [10]
2 years ago
15

How many grams of

Chemistry
2 answers:
laila [671]2 years ago
7 0

From the coefficients of the equation, we know that for every 3 moles of water consumed, 1 mole of diphosphorus trioxide is consumed.

This means we need to find the mass of 0.75 moles of diphosphorus trioxide.

  • The atomic mass of phosphorous is 30.973761998 g/mol.
  • The atomic mass of oxygen is 15.9994 g/mol.

So, the formula mass of diphosphorus trioxide is:

  • 2(30.973761998)+3(15.9994)=109.945723996 g/mol.

Thus, 0.75 moles have a mass of:

  • 0.75(109.945723996), which is about 82.5 g (to 3 sf)
anyanavicka [17]2 years ago
7 0
The answer is 82.5 g P2O3

you can use stoichiometry to solve for this problem. you’re given 2.25 mol H2O and when you look at your chemical reaction, you can see there’s 3 moles of H2O (look at the coefficients) and do the mole ratio. so in the chemical reaction, there’s 1 mol P2O3 and 3 mol H2O. you get your moles with that and since you need it in grams, you need to convert it using the P2O3 molar mass.

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Starting from position 3,5 go west 7 , then south 7, then east 4 what’s your ending point?
Vsevolod [243]

Answer:

-1, -2

Explanation:

West is left south is down east is right

5 0
3 years ago
a sample of a substance has a mass of 52.5g and displaces a volume of 4.2ml. what is the density of the substance
Lena [83]

Answer:

<h2>Density = 12.5 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 52.5 g

volume = 4.2 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{52.5}{4.2}  \\

We have the final answer as

<h3>Density = 12.5 g/mL</h3>

Hope this helps you

3 0
4 years ago
When making a guess and Retesting This information, a model or______________ may be formed which explains why something has occu
iVinArrow [24]

Experiment

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5 0
3 years ago
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Please answer ASAP I’ll give the brainliest!
lilavasa [31]

1. 1 mol=6.02.10²³ particles

\tt \dfrac{3.63\times 10^{23}}{6.02\times 10^{23}}=0.602~moles

2. Molar mass = Total atomic mass of component

AlBr₃ = Ar Al + 3. Ar Br

AlBr₃ = 27 + 3. 80 = 267 g/mol

3. mass = mol x MW

MW MnCl₂  = 55 + 2.35.5=126 g/mol

mass = 31.6 x 126 =3981.6 g

4. at STP, 1 mol =22.4 L, so for 5.6 L :

\tt \dfrac{5.6}{22.4}=0.25~moles

5. moles = mass : MW

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\tt moles=\dfrac{0.5}{32}=0.016

6. 1 mol = 22.4 L at STP

1 mol = 6.02.10²³ particles

moles for  8.20 x 10¹⁴ molecules

\tt \dfrac{8.2\times 10^{14}}{6.02\times 10^{23}}=1.36\times 10^{-9}

volume :

\tt 1.36\times 10^{-19}\times 22.4=3.05\times 10^{-8}~L

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