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3 years ago

How fast is the speed of light?

1 answer:

7 0

The speed of light is 299,792,458 meters per second in vacuum.
It's somewhat slower in any material substance, and different in
each substance.

(That's 186,282.4 miles per second.)

You might be interested in

A prairie dog runs into its burrow as a coyote approaches.This behavior helps the prairie dog

Nookie1986 [14]

This behavior helps the prairie dog from being prey upon by coyote.
Prairie dogs live in burrow and they normally do not move much away from their burrows. When they sense danger they will dash quickly back into their burrows. This behavioral adaptation protect them from predators.

4 0

4 years ago

Given: There are 39.95 grams of Argon (39.95 g/1 mole) and one mole has a volume of 22.4 Liters (1 mole/22.4 L). What is the vol

marta [7]

Answer:

$V_2=19.23L$

Explanation:

Hello,

In this case, by using the Avogadro's law which allows us to understand the volume-moles behavior as a directly proportional relationship:

$\frac{V_2}{n_2} =\frac{V_1}{n_1}$

We can compute the volume of 34.3 g of argon by representing it in mole as shown below:

$n_1=1 mol\\\\n_2=34.3g*\frac{1mol}{39.95g} =0.859mol$

Thus, we find:

$V_2=\frac{V_1*n_2}{n_1}=\frac{22.4L*0.859mol}{1mol} \\\\V_2=19.23L$

Best regards.

6 0

3 years ago

What is the answer for this!! plz it due today 5/6/20!!!

Furkat [3]

Answer:)

1. d

2.c

3.c

4.b

Explanation:

Because im smart

7 0

4 years ago

For most solids at room temperature, the specific heat is determined by oscillations of the atom cores in the lattice (each osci

Cloud [144]

Answer:

The specific heat of copper is $C= 392 J/kg\cdot ^o K$

Explanation:

From the question we are told that

The amount of energy contributed by each oscillating lattice site is $E =3 kT$

The atomic mass of copper is $M = 63.6 g/mol$

The atomic mass of aluminum is $m_a = 27.0g/mol$

The specific heat of aluminum is $c_a = 900 J/kg-K$

The objective of this solution is to obtain the specific heat of copper

Now specific heat can be defined as the heat required to raise the temperature of 1 kg of a substance by $1 ^o K$

The general equation for specific heat is

$C = \frac{dU}{dT}$

Where $dT$ is the change in temperature

$dU$ is the change in internal energy

The internal energy is mathematically evaluated as

$U = 3nk_BT$

Where $k_B$ is the Boltzmann constant with a value of $1.38*10^{-23} kg \cdot m^2 /s^2 \cdot ^o K$

T is the room temperature

n is the number of atoms in a substance

Generally number of atoms in mass of an element can be obtained using the mathematical operation

$n = \frac{m}{M} * N_A$

Where $N_A$ is the Avogadro's number with a constant value of $6.022*10^{23} / mol$

M is the atomic mass of the element

m actual mass of the element

So the number of atoms in 1 kg of copper is evaluated as

$m = 1 kg = 1 kg * \frac{10000 g}{1kg } = 1000g$

The number of atom is

$n = \frac{1000}{63.6} * (6.0*0^{23})$

$= 9.46*10^{24} \ atoms$

Now substituting the equation for internal energy into the equation for specific heat

$C = \frac{d}{dT} (3 n k_B T)$

$=3nk_B$

Substituting values

$C = 3 (9.46*10^{24} )(1.38 *10^{-23})$

$C= 392 J/kg\cdot ^o K$

5 0

3 years ago

How does a balanced chemical equation illustrate that mass is never lost or gained in a chemical reaction?

monitta

Answer:

Explanation:

Because if the equation is truly balanced, the elements on one side equal the element numbers on the other. Take a simple example.

Ba(OH)2 + 2HCl ==> BaCl2 + 2HOH

Now consider what is true.

Element Number of the left Number on the right.

Ba 1 1

O 2 2

H 4 4

Cl 2 2

Nothing has changed going from the left to the right. You may wonder how you get 4 for the hydrogens.

Ba(OH)2 has 2 hydrogens. You multiply the 2 by the hydrogens in the brackets.

2HCl = The 2 in front affects both the hydrogens and the chlorines. There are 2 hydrogens from the HCl

Total: 2 + 2 = 4 hydrogens. The right side is done the same way.

You are not getting different results on the right side than those that you had on the left. Mass is preserved. 1 Ba + 2 Os + 4Hs and 2 Cls on the left, gives the same numbers on the right. There is no loss of mass.

8 0

3 years ago