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Nikolay [14]
3 years ago
6

The reaction between halogens and alkanes is very rapid. true false

Chemistry
1 answer:
wel3 years ago
5 0
Halogens and Alkali react aggressively.
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Write the balanced chemical equation for the following reaction. Phases are optional. Solid calcium chlorate decomposes to form
Tanya [424]

Answer:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Explanation:

1)<u> Word equation (given)</u>

  • <em>calcium chlorate (solid) → solid calcium chloride (solid)  + oxygen (gas)</em>

2) <u>Chemical formulae of the reactant and products</u>:

  • <em><u>Calcium chlorate</u></em><em>: </em>

The most common oxidation states of chlorine are -1, +1, +3, +5, +7.

The suffix ate in chlorate means that chlorine atom is with the third lowest oxidation state (counting only the positive states). So, this is +5.

The oxidation state of calcium is +2.

Hence, the chemical formula of calcium chlorate is Ca(ClO₃)₂

  • <u><em>Calcium chloride</em></u>

The suffix ide in chloride means that chlorine is with oxidation state -1. Again the oxidation state of calcium is +2.

Hence, the chemical formula of calcium chloride is CaCl₂

  • <u><em>Oxygen</em></u>

Oxygen gas is a diatomic molecule, so its chemical formula is O₂.

  • <u><em>Phases</em></u>

The symbols s and g (in parenthesis) indicate the solid and gas phases respectively.

3) <u>Chemical equation</u>:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + O₂ (g)

That equation is not balanced becasue the number of O atoms in the reactant side and in the product side are different.

4)<u> Balanced chemical equation:</u>

Add a 3 as coefficient in front of O₂(g), in the product side to balance:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)

Verify that all the atoms are balanced:

Atom    Reactant side      Product side

Ca             1                           1

Cl              2                          2

O              3×2 = 6                2×3 = 6

Conclusion: the equation is balanced and the final answer is:

  • Ca(ClO₃)₂ (s) → CaCl₂ (s) + 3O₂ (g)
5 0
3 years ago
Biological oxidation-reduction reactions always involve:
kondor19780726 [428]

Answer:

b. transfer of electron(s).

Explanation:

An oxidation-reduction also called a redox reaction is a

chemical reaction in which electrons are transferred of between two species of reactants. It is a chemical reaction where the oxidation number of an atom, ion, or molecule, increases or decreases by losing or gaining electrons

3 0
2 years ago
The amount of matter in an object is known as
zavuch27 [327]
Mass......................

4 0
3 years ago
Read 2 more answers
What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?
34kurt
The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml.  This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.
6 0
3 years ago
Read 2 more answers
Plesse help asap!!!​
Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

8 0
3 years ago
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