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1 year ago

Find the amount in grams of 2.0 x 10^23 atoms Cu

Chemistry

1 answer:

-Dominant- [34]1 year ago

5 0

Answer:

21.182 g

Explanation:

There are about (6.0)(10^23) atoms in one mole of a substance, so the given sample has about 0.333 mol of Cu.

The atomic mass of Cu is 63.546 g/mol, meaning that the answer is about 21.182 g

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What is the gram formula mass of Ca3(PO4)2

Georgia [21]

Mass Molar of $Ca_{3} (PO_4)_2$
Ca = 3*40 = 120 amu
P = 2*31= 62 amu
O = (16*4)*2 = 64*2 = 128 amu
--------------------------------------
Mass Molar of $Ca_{3} (PO_4)_2$ = 120 + 62 + 128 = 310 g/mol

Therefore: What is the gram formula mass of Ca3(PO4)2 ?
Answer: 310 grams

6 0

3 years ago

A large company has recently suffered a traumatic workplace shooting. What forensics professional will executives most

olga_2 [115]

Answer:

The answer is forensic sociologist

I just took the exam and it’s rights

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2 years ago

What would be the bond order for He 2 2- molecule

LuckyWell [14K]

Answer:

In He2 molecule,

Atomic orbitals available for making Molecular Orbitals are 1s from each Helium. And total number of electrons available are 4.

Molecular Orbitals thus formed are:€1s2€*1s2

It means 2 electrons are in bonding molecular orbitals and 2 are in antibonding molecular orbitals .

Bond Order =Electrons in bonding molecular orbitals - electrons in antibonding molecular orbitals /2

Bond Order =Nb-Na/2

Bond Order =2-2/2=0

Since the bond order is zero so that He2 molecule does not exist.

Explanation:

8 0

2 years ago

_2. The temperature of a 100. mL sample of gas is increased while the volume it occupies decreases. The

yaroslaw [1]

Answer

the answer is b bro

Explanation:

i did my research and got it right

5 0

2 years ago

A metallurgical firm wishes to dispose of 1200 gallons of waste sulfuric acid whose molarity is 1.05 M. Before disposal, it will

Reil [10]

Answer:

The balanced chemical equation for this process:

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

$194.51 is the cost that the firm will incur from this use of slaked lime.

Explanation:

The balanced chemical equation for this process

$H_2SO_4(aq)+Ca(OH)_2(s)\rightarrow 2H_2O(l)+CaSO_4(aq)$

Moles of sulfuric acid = n

Volume of sulfuric acid disposed = V = 1200 gallons = 3.785 × 1200 L = 4,542 L

1 gallon = 3.785 Liter

Morality of the sulfuric acid = M = 1.05 m

$Molarity(M)=\frac{n}{V(L)}$

$n=m\times V=1.05 M\times 4,542 L=4,769.1 mol$

According to reaction, 1 mol of sulfuric acid reacts with 1 mole of calcium hydroxide.Then 4,769.1 moles of sulfuric acid will recat with ;

$\frac{1}{1}\times 4,769.1 mol=4,769.1 mol$ of calcium hydroxide

Mass of 4,769.1 moles of calcium hydroxide:

4,769.1 mol 74 g/mol = 352,913.4 g

= $\frac{352,913.4 }{453.6} pounds =778.03 pounds$

(1 pound = 453.6 grams)

Cost of 1 pound of slaked lime = $0.25

Cost of 778.03 pounds of slaked lime = $0.25 × 778.03 = $194.51

$194.51 is the cost that the firm will incur from this use of slaked lime.

3 0

3 years ago