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Setler79 [48]
2 years ago
14

What is specific heat capacity ​

Chemistry
2 answers:
LenaWriter [7]2 years ago
3 0

Answer:

<u>A</u>

Explanation:

kenny6666 [7]2 years ago
3 0

Answer:

a

Explanation:

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Indicate if the following statements are TRUE (T) or FALSE (F):
Aleks [24]

Answer:

a) T

b) T

c) F

d) F

e) T

f) T

g) T

h) F

I) F

j) F

k) F

l) F

Explanation:

The w/v concentration is obtained from, mass/volume. Hence;

%w/v= 50/1000= 5%

In the %w/w we have;

25g/100 g = 25% w/w

In combustion reaction, energy is given out hence it is exothermic.

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% by mass of carbon is obtained from;

8× 12/114 × 100 = 84.1%

All the ionic substances mentioned have very low solubility in water.

One mole of a substance contains the Avogadro's number of each atom in the compound.

There are two iron atoms so one mole contains 2× 55.85 g of iron.

Some sulphates such as BaSO4 are insoluble in water.

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The equation does not balance with the given coefficients because the number of atoms of each element on both sides differ.

The equation represents a decomposition of calcium carbonate as written.

3 0
3 years ago
How does removing thermal energy from liquid water affect the molecules in the water?
galina1969 [7]

Answer:

For deposition to happen, thermal energy must be removed from the gas. ... As water vapor loses thermal energy, it changes into solid frost. States of Water. Water is the only substance that exists naturally as a solid, a liquid, and a gas within Earth's temperature range.

Explanation:

3 0
3 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
How many mols of H2SO4 is in 0.80 L of 1.40 M H2SO4?
Hitman42 [59]
I think it’s 6 yw. Sorry if I’m wrong
7 0
2 years ago
What are lone pairs of electrons?
ozzi
A lone pair is a pair of valence electrons that are not shared with another atom and is sometimes called a non-bonding pair.
5 0
3 years ago
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