Answer:
The heat at constant pressure is -3,275.7413 kJ
Explanation:
The combustion equation is 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (l)
= (12 - 15)/2 = -3/2
We have;
Where R and T are constant, and ΔU is given we can write the relationship as follows;
Where;
H = The heat at constant pressure
U = The heat at constant volume = -3,272 kJ
= The change in the number of gas molecules per mole
R = The universal gas constant = 8.314 J/(mol·K)
T = The temperature = 300 K
Therefore, we get;
H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ
The heat at constant pressure, H = -3,275.7413 kJ.
Answer:
The value of x will be "1.4".
Explanation:
The given values are:
y = 9.6
z = 4.0
As we know,
The relation between x, y and z is:
⇒ 
and,
⇒ 
On substituting the given values, we get
⇒ 
⇒ 
<em>Answer:</em>
<em>Chemical equations must be balanced to satisfy the law of conservation of matter, that states that matter cannot be produced or destroyed in a closed system. The law of conservation of mass governs the balancing of a chemical equation.</em>
Explanation:
increases my factor of 10
Answer:
18.5 years
Explanation:
(6 x 10^23)/(10^15 x 1.03 x 3600 x 24 x 365)
Hope this helps!
