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2 years ago

If a(n) __________ is applied, the equilibrium shifts to relieve this change in conditions.

Chemistry

1 answer:

elixir [45]2 years ago

6 0

Answer:

the answer is D. stress

If a stress is applied, the equilibrium shifts to relieve this change in conditions.

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Which weather pattern has the most influence on the weather in North Carolina?

lina2011 [118]

A
That’s the real answer

8 0

3 years ago

Suppose you take a trip to a distant universe?...

zheka24 [161]

a. the orbital is defined by n,L, mL so (n, L, mL, -1), (n, L,mL, 0) and (n,L,mL, +1) and 3 electrons for any given orbital

b. in (n,L,mL,ms) format the first 12 elements would look like this

(1, 0, 0, +1)
(1, 0, 0, 0)
(1, 0, 0, -1)
(2, 0, 0, +1)
(2, 0, 0, 0)
(2, 0, 0, -1)
(2, 1, 0, +1)
(2, 1, 1, +1)<-----ANSWER
(2, 1, 0, 0)
(2, 1, 1, 0)
(2, 1, 0, -1)
(2, 1, 1, -1)
the idea is we don't pair up electrons until all the mL's have 1 so we wouldn't write
(2, 1, 0, +1)
(2, 1, 0, 0)
(2, 1, 0, -1)
then.
(2, 1, 1, +1)
(2, 1, 1, 0)
(2, 1, 1, -1)
because they would fill
(2, 1, 0, +1)1st
(2, 1, 0, 0)3rd
(2, 1, 0, -1)5th
then.
(2, 1, 1, +1)2nd
(2, 1, 1, 0)4th
(2, 1, 1, -1)6th
to pair (or rather triple up) electrons last
c. ideal gases are when each n level is full...
(1, 0, 0, +1)
(1, 0, 0, 0)
(1, 0, 0, -1)<----- ideal gas 3 electrons so 3 protons and atomic # = 3
(2, 0, 0, +1)
(2, 0, 0, 0)
(2, 0, 0, -1)
(2, 1, 0, +1)
(2, 1, 1, +1)
(2, 1, 0, 0)
(2, 1, 1, 0)
(2, 1, 0, -1)
(2, 1, 1, -1)<----- 2nd ideal gas12 e's so 12 p's and atomic # = 12

continuing on
(3, 0, 0, +1)
(3, 0, 0, 0)
(3, 0, 0, -1)
(3, 1, 0, +1)
(3, 1, 1, +1)
(3, 1, 0, 0)
(3, 1, 1, 0)
(3, 1, 0, -1)
(3, 1, 1, -1)..
(3, 2, 0, +1)
(3, 2, 1, +1)
(3, 2, 2, +1)
(3, 2, 0, 0)
(3, 2, 1, 0)
(3, 2, 2, 0)
(3, 2, 0, -1)
(3, 2, 1, -1)
(3, 2, 2, -1)<--- 3rd nobel gas atomic # = 30
hope it helps

5 0

3 years ago

Read 2 more answers

* The measurement for volume is? O grams O liters Oatom O mole

lord [1]

Answer: cubic units

6 0

3 years ago

Express the equilibrium constant for the following reaction.P4O10(s) ↔ P4(s) + 5 O2(g)K = [P4][O2]^5/[P4O10]K = [O2]^5K = [P4O10

Alex17521 [72]

Answer : The correct expression for equilibrium constant will be, $K=[O_2]^5$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$P_4O_{10}(s)\rightleftharpoons P_4(s)+5O_2(g)$

The expression of $K$ will be,

$K=[O_2]^5$

Therefore, the correct expression for equilibrium constant will be, $K=[O_2]^5$

7 0

4 years ago

What phase change is the following substance undergoing?

Dvinal [7]

Answer:

b melting

Explanation:

The phase change the substance is undergoing is from solid to liquid and this is called melting.

To understand this process, we need to know the the substance changing.
A substance that contains particles that are not easily compressed and packed is a solid.
Solids have fixed shapes and volumes.
Liquids can easily flow although they cannot also be easily compressed.

The phase change from solid to liquid is facilitated by a melting process.

5 0

3 years ago