The balanced equation for the neutralisation reaction is as follows
2H₃PO₄ + 3Mg(OH)₂ --> Mg₃(PO₄)₂ + 6H₂O
stoichiometry of H₃PO₄ to H₂O is 2:6
number of H₃PO₄ moles reacted - 0.24 mol
if 2 mol of H₃PO₄ form 6 mol of H₂O
then 0.24 mol of H₃PO₄ forms - 6/2 x 0.24 = 0.72 mol of H₂O
therefore 0.72 mol of H₂O are formed
Answer: Partial pressure of
at a depth of 132 ft below sea level is 2964 mm Hg.
Explanation:
It is known that 1 atm = 760 mm Hg.
Also, 
where,
= partial pressure of 
P = atmospheric pressure
= mole fraction of 
Putting the given values into the above formula as follows.


= 0.780
Now, at a depth of 132 ft below the surface of the water where pressure is 5.0 atm. So, partial pressure of
is as follows.

= 
= 2964 mm Hg
Therefore, we can conclude that partial pressure of
at a depth of 132 ft below sea level is 2964 mm Hg.
Answer:
301.7g
Explanation:
So there's 1 out of 3 are Oxygen.
905 / 3 = 301.7