Name the organic compound of ch2=chch2ch3

What mass of ni has as many atoms as there are n atoms in 63.0 g of no2?

adoni [48]

Answer : The mass of Ni is, 80.346 g

Solution :

First we have to calculate the number of moles.

$\text{Moles of }NO_2=\frac{\text{Mass of }NO_2}{\text{Molar mass of }NO_2}=\frac{63g}{46g/mole}=1.369moles$

Now we have to calculate the number of atoms of $NO_2$

As 1 moles $NO_2$ contains $6.022\times 10^{23}$ number of molecules

So, 1.369 moles $NO_2$ contains $1.369\times 6.022\times 10^{23}$ number of molecules

One $NO_2$ molecule has one nitrogen atom then $1.369\times 6.022\times 10^{23}$ number of molecules of $NO_2$ will contain $1.369\times 6.022\times 10^{23}$ number of nitrogen atoms

As per question number of Ni atoms is equal to the number of nitrogen atoms

Number of Ni atoms= $1.369\times 6.022\times 10^{23}$ atoms

Number of moles = $\frac{1.369\times 6.022\times 10^{23}}{6.022\times 10^{23}}=1.369moles$

Mass of Nickel = $Moles\times \text{Molecular mass}}$

Molecular mass of Nickel = 58.69 g/mol

Mass of nickel = $1.369mol\times 58.69g/mol=80.346grams$

8 0

3 years ago

Read 2 more answers

What do you call relative amounts of different sizes of mineral particles in a soil

TiliK225 [7]

Salt, silt, and clay particles

7 0

3 years ago

How many moles are in 213 grams of NaCl?

Nata [24]

Answer:

There are 3, 64 moles of NaCl.

Explanation:

First we calculate the mass of 1 mol of NaCl, starting from the atomic weights of Na and Cl obtained from the periodic table. Then we calculate themoles in 213 grams of NaCl, making a simple rule of three:

Weight NaCl= Weight Na + Weight Cl = 23 g + 35, 5 g= 58, 5 g/ mol

58,5 g ------1 mol NaCl

213 g---------x= (213 g x 1 mol NaCl)/ 58, 5 g= <em>3, 64 mol NaCl</em>

5 0

4 years ago

The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly sp

Kamila [148]

Answer:

the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

Explanation:

Given the data in the question;

To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose

we know that;

Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol

Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol

now, { metabolizing each gram }

moles of alanine = mass taken / molar mass

= 1g / 89.09 g/mol = 1/89.09 moles

moles of glucose = mass taken / molar mass

= 1g / 180.16 g/mol = 1/180.16 moles

In each molecule of alanine, we have 3 atoms of carbon.

Also, in each molecules of glucose, we have 6 atoms of carbon

so,

number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367

number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333

so ratio of energy will be the ratio of carbon atoms, which is;

⇒ 0.03367 / 0.0333 = 1.0111

Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

7 0

3 years ago

What are the two toxic byproducts of incomplete combustion?

Brums [2.3K]

Answer- C (water and carbon dioxide)

5 0

3 years ago