Answer:
The electric potential of the uniformly charge disk is 1392.1 V
Explanation:
Electric potential, for a uniformly charged disk at a distance A, is given as;
![V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B%5Csigma%7D%7B2%20%5Cepsilon%7D%20%5B%5Csqrt%7BA%5E2%20%2BR%5E2%7D%20-A%5D)
Where;
σ is the charge density = 1.40 μC/m³
ε is the permittivity of free space = 8.85 x 10⁻¹²
A is the distance above the disk = 40 cm = 0.4 m
R is the radius of the disk = 0.12 m
Substitute in these values into the equation above, we will have
![V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1.4%20X%2010%5E%7B-6%7D%7D%7B2X8%2C85X10%5E%7B-12%7D%7D%5B%5Csqrt%7B0.4%5E2%20%2B0.12%5E2%7D-0.4%5D%20%5C%5C%5C%5CV%20%3D%20%2879096.05%29%280.0176%29%20%3D%201392.1%20V)
Therefore, the electric potential of the uniformly charge disk is 1392.1 V
Since speed (v) is in ft/sec, let's convert our diameters from inches to feet:
1) 5/8in = 0.625in
0.625in × 1ft/12in = 0.0521ft
2) 0.25in × 1ft/12in = 0.021ft
Equation:
new velocity coming out of the hose then is
44 ft/sec
Answer:
clouds from when moist, warm rising air cools and expands in the atmosphere. The water vapor in the air condenses to form tiny water droplets which are the basis of clouds.
Explanation:
Answer:
Observation- The action or process of observing something or someone carefully or in order to gain information.
Hypothesis-a proposed explanation made on the basis of limited evidence as a starting point for further investigation.
Explanation:
