Answer:
KE = 0.162 KJ
Explanation:
given,
mass of bullet (m)= 20 g = 0.02 Kg
speed of the bullet (u)= 1000 m/s
mass of block(M) = 1 Kg
velocity of bullet after collision (v)= 100 m/s
kinetic energy = ?
using conservation of momentum
m u = m v + M V
0.02 x 1000 = 0.02 x 100 + 1 x V
20 = 2 + V
V = 18 m/s
now,
Kinetic energy of the block
KE = 162 J
KE = 0.162 KJ
The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × J/g per hour
<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>
E = 17.59 MeV
Mass = 2.014u + 3.016u
= 5.030u
Energy per Kg = (17.59××1.6×
) ÷ ( 5.030×1.66×
)
= 3.37× J/Kg
= 3.0× J/g
Rate of fuel burning in grams per hour = 3.0× × 3600
= 3.6×3.0×
= 1.08 × J/g per hour
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Answer:
1. Plateau where the temperature stays constant
2. Melting
3. Boiling points of the substance
Explanation:
The relationship between kinetic energy and temperature is given as follows;
Where;
= The average kinetic energy of the atom
R = The universal gas constant
= Avogadro's number
T = The temperature in Kelvin
Therefore, the kinetic energy increases as the temperature increases, however when the energy is not being converted into kinetic energy, the energy is stored as internal potential energy in the melted or evaporated state of the substance
Therefore, we have;
If energy is going into a system, but not being converted into kinetic energy, it will be converted into potential energy. This will be represented by a 1. <u>plateau where the temperature stays constant</u> on a heating curve, which occur at the 2. <u>melting</u> and 3. <u>boiling points of the substance.</u>