For circular motion.
Centripetal acceleration = mv²/r = mω²r
Where v = linear velocity, r = radius = diameter/2 = 1/2 = 0.5m
m = mass = 175g = 0.175kg.
Angular speed, ω = Angle covered / time
= 2 revolutions / 1 second
= 2 * 2π radians / 1 second
= 4π radians / second
Centripetal Acceleration = mω²r = 0.175*(4π)² * 0.5 Use a calculator
≈13.817 m/s²
The magnitude of acceleration ≈13.817 m/s² and it is directed towards the center of rotation.
Tension in the string = m*a
= 0.175*13.817
= 2.418 N
Answer:
f = 1 / [ 2*pi*R*C*Sqrt(2*N)
Explanation:
f = 1 / [ 2*pi*R*C*Sqrt(2*N) is the formula. Sorry I answered in English.
In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object
according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is
total momentum before collision = total momentum after collision
P₁ + P₂ = P'₁ + P'₂
where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.
P'₁ - P₁ = - (P'₂ - P₂)
so clearly gain in momentum of one object is same as the loss of momentum of other object