Please help! thank you!

Physics

1 answer:

icang [17]3 years ago

6 0

Answer:

A: The kinetic energy of the two vehicles is transferred to potential energy when it stops.

B: The more mass an object has the more kinetic energy it will have.

Explanation:

This may be the right answer for your question but if it isn't my bad.

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Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface

mina [271]

We have:

Total Energy: KE + GPE
KE (Kinetic Energy) = $\frac{1}{2} m*v^2$
GPE (Gravitational Potential Energy) = $m*g*h$

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
$TE = \frac{1}{2} m*v^2 + m*g*h$

Solving:
$TE = \frac{1}{2} m*v^2 + m*g*h$
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$TE = \frac{2.0*100}{2} + 1000$
$TE = \frac{200}{2} + 1000$
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$\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark$

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