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algol13
3 years ago
14

A worker with spikes on his shoes pulls on rope that is attached to a box that is resting on a flat, frictionless frozen lake. T

he box has mass m, and the worker pulls with a constant tension T at an angle θ = 40 ∘ above the horizontal. There is a strong headwind on the lake, which produces a horizontal force Fw that is pointed in the opposite direction than the box is being pulled. Draw a free-body diagram for this system. Assume that the worker pulls the box to the right. If the wind force has a magnitude of 30 N, with what tension must the worker pull in order to move the box at a constant velocity?

Physics
1 answer:
earnstyle [38]3 years ago
5 0

Answer:

a

The free body diagram is shown on the first uploaded image

b

The tension on the rope is  T=39.16 \ N  

Explanation:

From the  question we are told that

    The mass of the box is  m

    The tension on the box is  T

     The angle at which it is pulled is  \theta =  40^o

     The force produced by the strong head wind is Fw =  30 \ N

At equilibrium the net force acting on the block along the horizontal axis is zero i.e

     Tcos \theta -F_w = 0

substituting values

     Tcos (40) -30 = 0

     Tcos (40)  = 30

     T(0.76604))  = 30

     T=39.16 \ N      

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kolbaska11 [484]

Answer:

a= -1.2 m/s^2

Vi= 6.5 m/s

Vf= 0 m/s

t= 0-6.5/-1.2= <u>5.45 Sec</u>

Explanation:

4 0
3 years ago
The left side of the heart creates a pressure of 120 mm Hg by exerting a force directly on the blood over an effective area of 1
jeka57 [31]

Answer:

23.99N

Explanation:

Given:

Pressure created by the heart = 120mm of hg

converting the pressure into the standard unit of N/m²

1mm of hg = \frac{1}{760}atm=\frac{1}{760}\times 1.013\times10^5N/m^2

now, 120 mm of hg in N/m² will be

120mm of hg = \frac{12}{760}\times 1.013\times10^5N/m^2

also

given effective area = 15.0 cm² = 15 × 10⁻⁴m²

Now,

Force = Pressure × Area

thus,

Force exerted will be =  \frac{120}{760}\times 1.013\times10^5N/m^2 ×  15 × 10⁻⁴m²

or

Force exerted will be = 23.99N

4 0
3 years ago
Read 2 more answers
2.
saw5 [17]
U can infer that it’s a graph line
7 0
3 years ago
two campers pull a canoe. If the force of friction acting on the canoe is 84 N, then how much work does the two campers need to
sladkih [1.3K]
W=Fs 
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8 0
3 years ago
1. A note has a wavelength of 0.77955 m. If the speed of sound is 343.00 m/s, what pitch is this note? 2. A note has a wavelengt
AVprozaik [17]

Answer:

1.) 440 Hz

2.) 659.3 Hz

Explanation:

1.) Given parameters are:

wavelength = 0.77955 m.

speed of sound = 343.00 m/s

Frequency = speed/ wavelength

Substitute speed and wavelength into the formula

Frequency = 343/ 0.77955

Frequency = 439.99

Frequency = 440 Hz approximately

2.) The parameters given are:

wavelength = 0.52028 m.

speed of sound = 343.00 m/s

Using the same formula

Frequency = speed/wavelength

Substitute all the parameters into the formula

Frequency = 343 / 0.52028

Frequency = 659.3 Hz approximately

The pitch of a note depends on the frequency of the sound waves.

The pitch of a sound increases as the frequency of the sound waves increases.

5 0
3 years ago
Read 2 more answers
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