The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:

║E║ = ΔV/d

║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.

We are given the following values:

║E║= 10N/C

d = 3m

Plug these values in and solve for ΔV

10 = ΔV/3

ΔV = 30V

4 0

4 years ago

La estrella mas proxima a la tierra esta a 2 años de luz. Calcula esta distancia en unidades del SI

tino4ka555 [31]

Answer:

$2\ ly=1.89\times 10^{16}\ m$

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

$1\ ly=9.461\times 10^{15}\ m$

2 light-years means,

$2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m$

So, the required distance is equal to $1.89\times 10^{16}\ m$ .

5 0

3 years ago

Yo, help will give brainliest

kaheart [24]

Answer:

Explanation:

6 0

3 years ago

Bob has a brother, jim, who has a daughter named bertha. Bertha's daughter, jennifer, has a sister named penny. which of the fol

sammy [17]

Grandparent and grandchild

7 0

3 years ago

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