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lys-0071 [83]
3 years ago
12

A radioactive atom has just undergone nuclear decay. Its mass number is now four less than the original atom. Which type of nucl

ear decay has occurred?
Physics
1 answer:
fredd [130]3 years ago
4 0

Answer:

Explanation:

mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value

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Waves transport
Brilliant_brown [7]

Answer:

d)energy

Explanation:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

5 0
3 years ago
Miles is camping in Glacier National Park. In the midst of a glacier canyon,
valentina_108 [34]

Answer:

t=1.623 sec

Explanation:

The distance traveled before the echo is had is:

distance=2d, d=280\ m\\\\=280\times 2\\\\=560 \ m

Given the speed of sound as v=345m/s, we use the speed equation to solve for t:

v=\frac{d}{t}\\\\345\ m/s=\frac{560m}{t}\\\\t=\frac{560}{360}\\\\=1.623 \ s

Hence, it takes 1.623 seconds to hear the echo.

8 0
3 years ago
Samples of different materials, A and B, have the same mass, but the sample
madam [21]

Answer:

<u><em>A.)</em></u> The particles that make up material A have more mass than the

particles that make up material B.

HOPE that helps!!! :)

4 0
2 years ago
_____ occurs when light changes direction after colliding with particles of matter
KengaRu [80]
Scattering occurs when light changes direction after colliding with particles of matter.
4 0
3 years ago
Suppose you pluck a string on a guitar and it produces the note A at a frequency of 440 Hz. Now you press your finger down on th
MAVERICK [17]

Answer:

D. 550 Hz

Explanation:

Frequency for string is given by

f_{} =\frac{v}{2L}

where v is the speed of the wave, L = m is the length

Frequency is inversely proportional to the Length of the string

f \alpha \frac{1}{L} \\

from above relation we can write

\frac{f_{1}}{f_{2}} =\frac{L_{2}}{L_{1}}

The newly shortened string has 4/5 the length of the full string .i,e

\frac{440}{f_{2}} =\frac{\frac{4}{5}L_{1} }{L_{1}}\\f_{2}=\frac{440\times5}{4} \\f_{2}=550 Hz

Hence option D is correct

8 0
3 years ago
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