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denis-greek [22]
3 years ago
8

The relationship between linear velocity and angular velocity

Physics
1 answer:
bonufazy [111]3 years ago
7 0

In linear motion , when a body moves with uniform velocity , in time t , its linear displacement will be ;

S = r∅     S = vt

r∅ =  vt

r.∅ / t = v

As

v = rw

where ∅ = 90° is the angle between between radius vector r  and angular velocity w (omega )

In case ∅ ≠ 90° , we can write v = r w sin∅

It gives us v = w× r


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You drop a ball from a height of 10 meters. Each time the ball bounces, it
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C ,because kinetic energy is stored and there is energy needed for the ball to keep bouncing
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A goalie kicks a soccer ball straight vertically into the air. It takes 5.00 s for the ball to reach its maximum height and come
Yuliya22 [10]

Answer:

(a)    vo = 24.98m/s

(b)    t = 5.09 s

Explanation:

(a) In order to calculate the the initial speed of the ball, you use the following formula:

y=y_o+v_ot-\frac{1}{2}gt^2      (1)

y: vertical position of the ball = 2.44m

yo: initial vertical position = 0m

vo: initial speed of the ball = ?

g: gravitational acceleration = 9.8m/s²

t: time on which the ball is at 2.44m above the ground = 5.00s

You solve the equation (1) for vo and replace the values of the other parameters:

v_o=\frac{y-y_o+1/2gt^2}{t}        

v_o=\frac{2.44m-0.00m+1/2(9.8m/s^2)(5.00s)^2}{5.00s}\\\\v_o=24.98\frac{m}{s}

The initial speed of the ball is 24.98m/s

(b) To find the time the ball takes to arrive to the ground you use the equation (1) for y = 0m (ground) and solve for t:

0=24.98t-\frac{1}{2}(9.8)t^2\\\\t=5.09s

The time that the ball takes to arrive to the ground is 5.09s

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3 years ago
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11 hours and 24 minutes total of sleep. Nice.

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3 years ago
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Answer:

W = 0.842 J

Explanation:

To solve this exercise we can use the relationship between work and kinetic energy

         W = ΔK

In this case the kinetic energy at point A is zero since the system is stopped

         W = K_f                (1)

now let's use conservation of energy

starting point. Highest point A

          Em₀ = U = m g h

Final point. Lowest point B

         Em_f = K = ½ m v²

energy is conserved

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to find the height let's use trigonometry

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so at the height is

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we substitute

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let's calculate

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3 years ago
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Answer:

The number of paces it would take to get to the Moon is 213,555,556 paces

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Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;

n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)

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The number of paces it would take to get to the Moon = n = 213,555,556 paces

5 0
3 years ago
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