C ,because kinetic energy is stored and there is energy needed for the ball to keep bouncing
Answer:
(a) vo = 24.98m/s
(b) t = 5.09 s
Explanation:
(a) In order to calculate the the initial speed of the ball, you use the following formula:
(1)
y: vertical position of the ball = 2.44m
yo: initial vertical position = 0m
vo: initial speed of the ball = ?
g: gravitational acceleration = 9.8m/s²
t: time on which the ball is at 2.44m above the ground = 5.00s
You solve the equation (1) for vo and replace the values of the other parameters:

The initial speed of the ball is 24.98m/s
(b) To find the time the ball takes to arrive to the ground you use the equation (1) for y = 0m (ground) and solve for t:

The time that the ball takes to arrive to the ground is 5.09s
Answer:
11 hours and 24 minutes total of sleep. Nice.
Explanation:
Since its going from pm to am, We have to go past 12 to 1 and go to 9 hours am, then add 42 by 24 minutes to get to the 6 minutes past 10.
#teamtrees #WAP (Water And Plant)
Answer:
W = 0.842 J
Explanation:
To solve this exercise we can use the relationship between work and kinetic energy
W = ΔK
In this case the kinetic energy at point A is zero since the system is stopped
W = K_f (1)
now let's use conservation of energy
starting point. Highest point A
Em₀ = U = m g h
Final point. Lowest point B
Em_f = K = ½ m v²
energy is conserved
Em₀ = Em_f
mg h = K
to find the height let's use trigonometry
at point A
cos 35 = x / L
x = L cos 35
so at the height is
h = L - L cos 35
h = L (1-cos 35)
we substitute
K = m g L (1 -cos 35)
we substitute in equation 1
W = m g L (1 -cos 35)
let's calculate
W = 0.500 9.8 0.950 (1 - cos 35)
W = 0.842 J
Answer:
The number of paces it would take to get to the Moon is 213,555,556 paces
Explanation:
The given length of Mr Galan's paces = 1.8 m/pace
The distance from the Earth to the Moon is, 384,400 km = 384,400,000 m
Therefore, the number of paces, "n", it would take to get to the Moon from the Earth is given as follows;
n = (The distance from the Earth to the Moon)/(The length of each Mr Galan's paces)
∴ n = 384,400,000 m/(1.8 m/pace) = 213,555,556 paces
The number of paces it would take to get to the Moon = n = 213,555,556 paces