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Vsevolod [243]
3 years ago
9

Tafu is working with subatomic particles in the physics lab. a positron is traveling in a straight line down the particle accele

rator. tafu models its position with the function p(t)= t2 t â 1 where t>1. in the limit calculations below, if you need to use -â or â, enter -infinity or infinity. (a) calculate the limit
Physics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

Infinity

Explanation:

When you have a limit approaching infinity one method you can use is to remember that the highest power dominants all of the other ones so when we have (t^2)/t-1 like in your problem, we see that t^2 has the highest power of 2 so if that's going to infinity and it's not being divided by any powers higher than it will just be inifinity.

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A car is traveling at 7.0 m/s when the driver applies the brakes. The car moves 1.5 m before it comes to a complete stop. If the
viva [34]

Answer:

d. 6.0 m

Explanation:

Given;

initial velocity of the car, u = 7.0 m/s

distance traveled by the car, d = 1.5 m

Assuming the car to be decelerating at a constant rate when the brakes were applied;

v² = u² + 2(-a)s

v² = u² - 2as

where;

v is the final velocity of the car when it stops

0 = u² - 2as

2as = u²

a = u² / 2s

a = (7)² / (2 x 1.5)

a = 16.333 m/s

When the velocity is 14 m/s

v² = u² - 2as

0 = u² - 2as

2as = u²

s = u² / 2a

s = (14)² / (2 x 16.333)

s = 6.0 m

Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.

The correct option is d

4 0
3 years ago
What is the specific heat capacity of water?
Finger [1]
The specific heat of water is 4.186.
8 0
3 years ago
A closely wound circular coil has a radius of 6.00 cmand carries a current of 2.65 A. How many turns must it have if the magneti
ad-work [718]

Answer:

Given:

radius of the coil, R = 6 cm = 0.06 m

current in the coil, I = 2.65 A

Magnetic field at the center, B = 6.31\times 10^{4} T

Solution:

To find the number of turns, N, we use the given formula:

B = \frac{\mu_{o}NI}{2R}

Therefore,

N = \frac{2BR}{\mu_{o}I}

N = \frac{2\times 6.31\times 10^{4}\times 0.06}{4\pi \times 10^{- 7}\times 2.65}

N = 22.74 = 23 turns (approx)

 

8 0
3 years ago
An ideal heat engine absorbs 97.2 kJ of heat and exhausts 83.8 kJ of heat in each cycle. What is the efficiency of the engine?
r-ruslan [8.4K]

Answer:

13.7%

Explanation:

Given that,

Heat absorbed by the engine = 97.2 kJ

Heat exhausted by the engine in each cycle = 83.8 kJ

We need to find the efficiency of the engine. It is calculated by the formula.

\eta=1-\dfrac{Q_e}{Q_a}\\\\=1-\dfrac{83.8}{97.2}\\\\=0.137\\\\=13.7\%

so, the efficiency of heat engine is 13.7%.

5 0
3 years ago
If the is the absense of light is the dark. thennnnnnnnnn since there is light particles. is there dark particles?if not then im
TEA [102]
sis
I’m dum too
Have a good day
7 0
2 years ago
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