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Lena [83]
3 years ago
11

Explain the working and principle of perisocope.​

Physics
1 answer:
aksik [14]3 years ago
6 0

Answer:

a periscope use total internal reflection to allow us to see things

the reflection happens at 45°

Explanation:

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The diagram shows a spectrometer being used to analyze a sample of a solution.
fredd [130]

Answer

B. X

A plate of glass or metal ruled with very close parallel lines, producing a spectrum by diffraction and interference of light.

diffraction grating is an optical component that splits and diffracts light into several beams travelling in different directions. The light emerges with its colours separated.

4 0
3 years ago
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Explain why a balloon filled with air cannot float in the middle of a room without moving downwards but a helium balloon of the
ELEN [110]
Helium is less dense than normal air
6 0
3 years ago
Whenever two Apollo astronauts were on the surface of the Moon, a third astronaut orbited the Moon. Assume the orbit to be circu
inysia [295]

Answer:

v  =  1,582 \ \frac{m}{s}

Explanation:

We know that for circular motion the centripetal acceleration a_c is:

a_c = \frac{v^2}{r}

where v is the speed and r is the radius.

The centripetal acceleration for the astronaut must be the gravitational acceleration due to the gravity, as there are no other force. So

a_c = 1.27 \frac{m}{s^2}.

The radius of the orbit must be the radius of the Moon, plus the 270 km above the surface

r = 1.7 * 10^6 \ m + 270  \ km

r = 1.7 * 10^6 \ m + 270 * 10^3 \ m

r = 1.7 * 10^6 \ m + 0.270 * 10^6 \ m

r = 1.97 * 10^6 \ m

We can obtain the speed as:

v^2  = a_c r

v  = \sqrt{a_c r}

v  = \sqrt{1.27 \frac{m}{s^2} * 1.97 * 10^6 \ m}

v  = \sqrt{ 2.509 \ 10^6 \ \frac{m^2}{s^2}}

v  =  1.582 \ 10^3 \ \frac{m}{s}

v  =  1,582 \ \frac{m}{s}

And this is the orbital speed.

7 0
3 years ago
A cyclist traveling at constant speed of 12m/s when he passes a stationary bus.The bus starts moving just as the cyclist passes
Bogdan [553]

Answer:

A.) 8 seconds

B.) 16 seconds

C.) 48 m

Explanation:

Given that a cyclist traveling at constant speed of 12 m/s

and the bus accelerates uniformly at 1.5ms²

A.) The bus has the following parameters

Acceleration a = 1.5 m/s^2

Initial velocity U = 0. Since the bus is starting from rest.

Final velocity V = 12 m/s

Use equation one of linear motion.

V = U + at

Substitute V, U and a into the formula

12 = 0 + 1.5t

1.5t = 12

t = 12/1.5

t = 8 seconds

Therefore, the bus reach the same speed as the cyclist at 8 seconds.

B.) For the cyclist moving at constant speed, acceleration a = 0. Using second equation of motion

h = Ut + 1/2at^2

Since a = 0, the equation is reduced to:

h = Ut.

Also, for the bus,

h = Ut + 1/2at^2

Equate the two equations since the h is the same

Ut = Ut + 1/2at^2

Substitute all the parameters into the formula

12t = 0 + 1/2 × 1.5t^2

12t = 0.75t^2

0.75t = 12

t = 12/0.75

t = 16 seconds

Therefore, the bus takes 16 seconds to catch the cyclist

C.) Use third equation of linear motion.

V^2 = U^2 + 2as

Where s = distance

Substitute V, U and a into the formula

12^2 = 0 + 2 × 1.5 S

144 = 3S

S = 144/3

S = 48 m

8 0
3 years ago
.Why does it take double the applied force to move a mass double the size?
Likurg_2 [28]

Answer:

NVIDIA GeForce RTX 3080 10GB GDDR6X PCI Express 4.0 Graphics Card

Explanation:

6 0
3 years ago
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