Answer:
Explanation:
Given that,
Radius r = 15cm = 0.15m
Area of the circular loop can be determined using the formula for area of a circle
A = π r²
A = π × 0.15²
A = 0.0708 m²
Magnetic field B = 1.2T in positive z direction
B = 1.2 •k T.
If loop is remove from the field in the time interval
∆t = 2.3ms = 2.3×10^-3s
We want to find the average EMF and it is given as
ε = —∆Φ/∆t
The final flux is zero
Φf = 0
Where magnetic flux is given as
Φi = BA Cosθ
Where θ=0 since the area and the magnetic field point in the same direction.
Φi = BA Cos0
Φi = BA
Φi = 1.2 × 0.0708
Φi = 0.0848 Vs
Then, ε = —∆Φ/∆t
ε = —(Φf — Φi) / ∆t
ε = —(0-0.0848) / (2.3×10^-3)
ε = 0.0848 / (2.3×10^-3)
ε = 36.88 V
The EMF is 36.88 Volts
D. Energy / Time is that formula.
The second one (4.1 kg ball)
This is because the mxv is greater than the other one.
For the 4.1kg ball, the force it’s moving on is 4.92N
As for the 3.2kg ball, it’s moving with a force of 0.9N. Much less than the other one.
Answer:
1.1 Two poles: North and South Poles.
1.2 - Staple pin - Nail - Tip of my phone charger - Metal keys - Cloth Hanger
1.3 - Wooden bed cot - Plastic pen - Game pad - Wooden shelf - Paper - A T-shirt
1.4 Yes
1.5 No
