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3 years ago

6

It took 3 seconds for an object that was thrown up with velocity vo from

1 answer:

otez555 [7]3 years ago

5 0

Answer:

ik u got it bc this was 2 weeks ago

Explanation:

but yes and yuea

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Jake drove 160 kilometres in 2 hours. What was his speed, in kmh-1

ruslelena [56]

Answer:

80 kmh

Explanation:

IDK lol i just divided it by 2 because he drove 80 kilometres in one hour

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3 years ago

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A building that is 105.50 ft. feet tall is casting a shadow that is 37.50 ft. feet. If the building next to it, is casting a sha

Arlecino [84]

115.35 ft

Set the proportion up 37.50/105.50 = 41/x and solve for x

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3 years ago

Which simple machines make up a wheel barrow

7nadin3 [17]

Answer:

a lever and a wheel and axle (i guess)

Explanation:

don't have any

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3 years ago

A heated piece of metal cools according to the function c(x) = (.5)^(x _ 11), where x is measured in hours. A device is added th

Agata [3.3K]

You just need to replace x with 5 in each function

.5^5 - 11
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.5 ^-6
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64 - 8 = 56 A Celcius

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2 years ago

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A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago