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3 years ago

11

What gives an object gravity?

1 answer:

Oksana_A [137]3 years ago

8 0

We don't know WHY there are gravitational forces that attract everything
to everything else.

We DO know that the more mass is involved, the stronger the forces are,
and we know that if an object had no mass then it wouldn't be affected by
gravity. So you could say that it's MASS that gives an object gravity, and
the more mass the object has, the more gravity it has.

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A hockey puck with a mass of 0.175 kg slides over the ice. The puck initially slides with a speed of 5.25 m/s, but it comes to a

Neko [114]

Answer:

1.70 J

Explanation:

The heat dissipated is the difference in the kinetic energies.

This is given by

$E = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

$v_i$ and $v_f$ are the initial and final velocities.

With <em>m</em> = 0.175 kg,

$E = \frac{1}{2}\times0.175(2.85^2 - 5.25^2) = -1.701\text{ J}$

The negative sign appears because energy is lost.

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3 years ago

The most dangerous thing for a motorcyclist passing parked cars is

jeka94

The main danger is vehicles making u-turns or pulling out without signalling.

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3 years ago

When one "throws” a punch, the forearm applies force to the fist. Consider a(n) 0.75 kg fist that goes from rest to a

deff fn [24]

Formula for acceleration

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3 years ago

When 1,250^3/4 is written in simplest radical form, which value remains under the radical?

GaryK [48]

Answer:

$125\sqrt[4]{8}$

Explanation:

A number of the form

$a^{\frac{m}{n}}$

can be re-written in the radical form as follows:

$\sqrt[n]{a^m}$

In this problem, we have:

a = 1,250

m = 3

n = 4

So, if we apply the formula, we get

$1,250^{\frac{3}{4}}=\sqrt[4]{(1,250)^3}$

Then, we can rewrite 1250 as

$1250 = 2\cdot 5^4$

So we can rewrite the expression as

$=\sqrt[4]{(2\cdot 5^4)^3}=5^3 \sqrt[4]{2^3}=125\sqrt[4]{8}$

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3 years ago

Read 2 more answers

A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed

Ronch [10]

Answer:5.7m/s

Explanation:

Mass=1kg

Initial velocity=u=8m/s

height=h=1.6m

Final velocity =v

Acceleration due to gravity=g=9.8m/s^2

v^2=u^2-2xgxh

v^2=8^2-2x9.8x1.6

v^2=8x8-2x9.8x1.6

v^2=64-31.36

v^2=32.64

Take the square root of both sides

√(v^2)=√(32.64)

v=5.7

Speed at the height of 1.6m is 5.7m/s

8 0

3 years ago