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tia_tia [17]
3 years ago
8

A temperature of 34ºF is equal to ____________________ kelvin.

Physics
1 answer:
lara31 [8.8K]3 years ago
6 0
 Kelvin = (Fahrenheit - 32) * 5 / 9 + 273.15<span> 

then 
k = (34 - 32) *5/9 + 273.15
k = 274.26 </span>
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What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall
andrey2020 [161]

Answer:

D_{s} ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

     I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere               Is_{cm} = 2/5 M R²

Spherical shell   Ic_{cm} = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

    I = I_{cm} + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

     D = 2R

    Ic = Ic_{cm} + M D²

    Ic = 2/3 MR² + M (2R)²

    Ic = M R² (2/3 + 4)

    Ic = 14/3 M R²

The sphere

    Is =Is_{cm} + M [D_{s}²

    Is = Ic

    2/5 MR² + M D_{s}² = 14/3 MR²

    D_{s}² = R² (14/3 - 2/5)

    D_{s} = √ (R² (64/15)

    D_{s} = 2,066 R

3 0
3 years ago
A. In one short sentence, explain why we call the force of gravity an attractive force.
kondor19780726 [428]

Answer:

Explanation:

(a) The force of gravity is called an attractive force because it is the force (although weak) in which a planetary body or matter uses to attract an object towards itself.

(b) Yes, it does and the formula for force of gravity between any two object is

F = G\frac{m1m2}{r}

where m1 and m2 are masses of the first and second object respectively

r is the distance between the center of the two masses

G is the gravitational constant

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3 years ago
Plz help
katrin2010 [14]

The particles of the medium (slinky in this case) move up and down (choice #2) in a transverse wave scenario.

This is the defining characteristic of transverse waves, like particles on the surface of water while a wave travels on it, or like particles in a slack rope when someone sends a wave through by giving it a jolt.

The other kind of waves is longitudinal, where the particles of the medium move "left-and-right" along the direction of the wave propagation. In the case of the slinky, this would be achieved by giving a tensioned slinky an "inward" jolt. You would see that such a jolt would give rise to a longitudinal wave traveling along the length of the tensioned slinky. Another example of longitudinal waves are sound waves.

4 0
3 years ago
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Aleks [24]

Answer:

Probably competition with television news-

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6 0
2 years ago
Based on experimental observations, the acceleration of a particle is defined by the relation a = -(0.1 + sin x/b), where a and
Fiesta28 [93]

Answer:

Velocity,v = 0.323 m/s

Explanation:

The acceleration of a particle is given by :

a=-(0.1+sin\dfrac{x}{b})

b = 0.8 m when x = 0

Since, a=v\dfrac{dv}{dx}  

v\dfrac{dv}{dx}=-(0.1+sin\dfrac{x}{b})  

\int{v.dv}=\int{-(0.1+sin\dfrac{x}{b})}.dx

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c

At x = 0, v = 1 m/s

\dfrac{1}{2}=0.8+c

c=-0.3

\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3

At x = -1 m

\dfrac{v^2}{2}=-0.1(-1)+0.8cos\dfrac{(-1)}{0.8}-0.3

{v^2}=0.1045

v = 0.323 m/s

So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.

8 0
3 years ago
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