Explanation: So to make the equations balance we will put numerical coefficients on each variable so that the total number of atoms will be equal on each side.
For number 1 we will put 2 on AB to balance the reactant. For number 2, we will write 2 on A and 3 in B in the reactant side. For number 3, write 2 on A and 3 on B2 in the reactant and 2 on AB3 in the product side. For number 4, the coeffecients are 1:2:2 and lastly on number 5 the coeffencients are 2:3:2.
To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps; 1. Water at 0°C to ice at 0°C The heat of fusion of ice is 334 J/g; Heat = 78.1 × 334 = 26085.4 Joules 2. Ice at 0°C to -57.1°C Specific heat of ice is 2.108 J/g Heat = 78.1 × 2.108 J/g = 164.6348 Joules Thus the total heat energy released will be; 26085.4 + 164.6348 = 26250.0348 J or 26.250 kJ
