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4 years ago

What are the number if protons, neutrons, and electrons

Chemistry

1 answer:

marishachu [46]4 years ago

5 0

protons and electrons are both always the atomic number which is 9 in this case.

For neutrons you subtract the atomic number (9) from the weight of the atom (18.998) some teachers will want you to round to the nearest whole (19). We do this because the number of protons is the atomic number so if you subtract the protons from the whole weight of the atom you would have the electrons and neutrons left. Since electrons weigh so little we don't have to subtract them. Weighing neutrons and electrons would be like weighing an elephant (neutrons) and then putting one marshmallow on the scale (electron).

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Barium nitrate (Ba(NO3)2) reacts with sodium chloride (NaCl) in a double replacement (displacement) reaction, shown below.

Nesterboy [21]

Answer:

you know that they will be a displacement reaction that will form a barium salt:

Ba(NO3)2+ 2NaCl--> BaCl2 + 2NaNO3

So now that we have that formula and the molecular weight we can determine how much salt will be made. So here we convert the grams to moles

(42.3g Ba(NO3)2)*(1 mole/261.34g) = 0.16185 mol

In the molecular formula we know that 1 mole of Barium nitrate will create 1 mole of Barium chloride, so in this case (in a perfect world) you should get 0.16185 mole of barium chloride (208.23 g/mol) that we then have to convert to grams.

(0.16185 mol BaCl2) * ( 208.23 g/mol) = 33.7037 g of Barium Chloride (rounded to 3 significant digits = 33.7g)

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2 years ago

Question 3 Multiple Choice Worth 4 points)

Leviafan [203]

Answer: C.

Explanation:

Its C because a controlled experiment would make the pill's statement true.

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8 0

3 years ago

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Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea

Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

$\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}$

Molar mass of n-propanol = 60.09 g/mole

$\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole$

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

= 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

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3 years ago

a piece of tin foil has a volume of 0.645 ml to the 3rd if a piece measures 10.0 mm by 12.5 m what is the thickness of the foil

tatyana61 [14]

Explanation:

Fundamentally the aluminum foil is a rectangular prism. It has a length, a width, and a thickness.

The volume of a rectangular prism is expressed as

$V = l * w * h$

If we know the volume and two of the three dimensions, we can rearrange the equation to solve for the thickness.

$h = V/(l*w)$

But we should also be sure to confirm our units.

A liter is defined as 1000 cm^3. Therefore a mL is equal to 1 cm^3.

You should convert the units of measure given in the problem statement such that the units are aligned. For example, 10.0mm will be 1 cm and 12.5m will be 1250 cm. This will give you a height in cm.

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3 years ago

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ElenaW [278]

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4 years ago

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