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melomori [17]
2 years ago
8

How many points need to be removed from this graph so that it will be a function?

Mathematics
1 answer:
DiKsa [7]2 years ago
7 0
3 points. Do the vertical line test.
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The axis of symmetry for the graph of the function is f(x) = x2 + bx + 10 is x = 6. What is the value of b?
joja [24]

Answer:

b=-12

Step-by-step explanation:

we have

f(x)=x^{2}+bx+10

we know that

The equation of a vertical parabola into vertex form is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex of the parabola

and the axis of symmetry is equal to x=h

In this problem we have the axis of symmetry x=6

so

the x-coordinate of the vertex is equal to 6  

therefore

For x=6+1=7 -----> one unit to the right of the vertex

Find the value of f(7)

f(7)=7^{2}+b(7)+10

f(7)=59+7b

For x=6-1=5 -----> one unit to the left of the vertex

Find the value of f(5)

f(5)=5^{2}+b(5)+10

f(5)=35+5b

Remember that

f(5)=f(7) ------> the x-coordinates are at the same distance from the axis of symmetry

so

59+7b=35+5b ------> solve for b

7b-5b=35-59

2b=-24

b=-12


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Step-by-step explanation:

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