So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

Next, square both sides:

Next, subtract x and add 2 to both sides of the equation:

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

Now you can rewrite the equation as 
Now, apply the Zero Product Property and solve for x as such:

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
27$ because you do 20*15*12 then 3600*0.09 and divide that answer by 12 which is 27
Answer:
21. B. Graph Z
23. A. neither function nor relation
24. D. relation only
Step-by-step explanation:
21. Graph Z is the only graph which does not pass the vertical line test
23. The graph does not pass the vertical line test, AND it is not merely given x and y points like a relation. It is graphed as a squiggly line with no given x and y points, therefore you could not make a relation from it either.
24. There is an x value of -4 twice, meaning the set does not pass the vertical line test, HOWEVER, it is a given collection of x and y values, making it a relation.
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