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mr_godi [17]
2 years ago
8

Help me plaese on this

Physics
2 answers:
Crazy boy [7]2 years ago
5 0

Answer:

visible light waves

Explanation:

what

Anna35 [415]2 years ago
5 0

Answer:

Gamma ray

Explanation:

B/c The electromagnetic spectrum includes, from longest wavelength to shortest: radio waves, microwaves, infrared, optical, ultraviolet, X-rays, and gamma-rays.

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45. An object with a mass of 25 kg accelerates east at a rate of 7 m/s? What fiet force is acting on the object?
ZanzabumX [31]

Answer:

According to newton's second law of motion F=ma so

Explanation:

Data:-M=25kg ,a=7m/s² F=? ,solution:-F=ma ,F=25×7=175kgm/s² or N

6 0
4 years ago
A submersible pump is put under the water at the bottom of a well and is used to push water up through a pipe. What minimum outp
Fantom [35]

Answer:

The Required pressure for this situation is P= 735000Pa

Explanation:

In Determining the required pressure in this situation we use two equations

First one is

F = mg = (ρhA)g

And Second one is

P = F/A = (ρhAg)/A Where P is pressure

We get

P = ρhg  

since g = 9.8 m/s and h is given that is 75m and ρ = 1000 kg/m^3

so

P = (9.8 m/s)(1000 kg/m^3)(75) we get

P = 735000 Pa

6 0
4 years ago
7 One lb of Refrigerant 134a contained within a piston–cylinder assembly undergoes a process from a state where the temperature
julsineya [31]

Answer:

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb ^ {\circ} R}

Explanation:

A) In order to solve the table it is necessary to consult tables A11-E and A10E for refrigerant R134-a

In this way we obtain that:

S_1 = S_f = 0.0648 \frac {BTU} {Lb. ^ {\circ} R}

In this way,

S_2 = S_f + x_2 (S_g-S_f) = 0.0902 + 0.5 (0.2161-0.0902)

S_2 = 0.15315 \frac {BTU} {Lb ^ {\circ} R}

In this way the entropy change is,

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb. ^ {\°} R}

B) Whenever entropy yields a positive result, the process can be carried out adiabatically.

7 0
3 years ago
On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
irinina [24]

Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

3 0
3 years ago
5.37 At steady state, a power cycle develops a power output of 10 kW while receiving energy by heat transfer at the rate of 10 k
Anika [276]

Answer: minimum theoretical value of T = 750k

Explanation:

Assuming the the cycle is reversible and is ideal then

Wnet/Qh = Nmin .... equa 1

Equation 1 can be rewritten as

(Th -TL)/ Th ...equation 2

Th= temp of hot reservoir

TL= temp of low reservoir= 300

Wnet = power generated=10kw

He = energy transfer=10kj per cycle

Qhe = power transfer = (100/60)*10Kj = 16.67kw

Sub into equat 1

Nmin = 10/16.67 = 0.6

Sub Nmin into equation 2

Th = -TL/(Nmin -1) = -300k/(0.6 - 1)

Th =750k

4 0
3 years ago
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