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Zina [86]
3 years ago
10

4. For a series of experimentally measured values give the definition of (a) average or mean value (b) the deviation from the me

an (c) average deviation (d) standard deviation 5. Explain how one can express experimental result using the quantities discussed in (4).
Physics
1 answer:
Naya [18.7K]3 years ago
3 0

Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

d) σ = √(1/n-1  ∑ Dx_{i}² )

Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

  (x_average + - Δx_average)

  σ

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Tatiana [17]

Answer:

The Height is  H = 70.02 m

Explanation:

We are given that the

                         Initial length is  = 40000\ Km = 40,000 *10^{3} m

from what we are told in the question the circumference of the circle is = 40,000 Km

  This means that the Radius would be :

         Let C denote the circumference

      So  

               C = 2 \pi r

      =>     r = \frac{C}{2 \pi}

               r = \frac{40,000}{2 \pi } = \frac{40,000*10^{3}}{2 *3.142}  = 6.365*10^6 m

We are told that 1-meter bar of steel that increases its temperature by 1 degree C will expand 11*10^{-6} meters

Hence

       The final length would be

                            40000*10^3 *(T + \alpha  )

Where T is the change in  temperature  \alpha is the Coefficient of linear expansion for steel

  let L_{final} denote the final length

   So

        L_{final} =40000*10^{6} *[1+ 11*10^{-6}]

                  = 40000440 \ m

 Now the Height is mathematically represented as

         Height(H) \ = \frac{change \ in \ radius \ }{2 \pi}

                       = \frac{(40000440-40000*10^3)}{2*3.142}

                       = 70.02m

3 0
3 years ago
A projectile is launched with speed of 128 m/s, at an angle of 60° with the horizontal. After 2.0 s, what is the vertical compon
Natali5045456 [20]

Answer:

a) 91 m/s

b) 111 m/s

Explanation:

v = u + at

v = 128sin60 + (-9.8)(2.0) = 91.25125... m/s

v = √(vx² + vy²) = √((128cos60)² + 91.25125²) = 111.4575... m/s

5 0
3 years ago
A velocity selector, in which charged particles of a specific speed pass through undeflected while those of greater or lesser sp
uranmaximum [27]

Answer:

a) 351351.35m/s

b) 1.044*10^{-8}kg/C

Explanation:

a) Electric force and magnetic force over the charge must have the same magnitude. From there we can compute the seep of the charge.

F_E=F_B\\\\qE=qvB\\\\v=\frac{E}{B}=\frac{1.95*10^{5}V/m}{0.555T}=351351.35\frac{m}{s}

b) the mass-charge ratio is given by:

\frac{m}{q}=\frac{rB}{v}=\frac{(6.61*10^{-3}m)(0.555T)}{351351.35m/s}=1.044*10^{-8}\frac{kg}{C}

hope this helps!!

5 0
3 years ago
A forensics investigator discharged an assault rifle-replica such that the bullet fired at an angle of 30 (degrees) off the hori
aliina [53]

Answer:

Initial y-component of speed

Vy = 28 * sin 30 = 14 m/sec vertically

1/2 m Vy^2 = 2 m g h    conservation of energy of y-component

h = Vy^2 / (2 * g) = 14^2 / (2 * 9.8) = 10 m

4 0
3 years ago
PLZZZ HELPP ASAP!!!!
Tamiku [17]

Answer:

1.68N

Explanation:

W=F*d

KE=1/2*M*V^2

M=32kg

V= 5.1m/s

D=50m

0.5(32)(5.1^2)= 416 J

Initial energy=500 J

final energy= 416 J

lost energy= 500-416

heat lost to friction=84 J

84=F*50

84/50=F*50/50

F=1.68N

3 0
3 years ago
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