Answer:
2 x 10^20 N
Explanation:
Me = 5.98 x 10^24 kg
Mm = 7.36 x 10^22 kg
r = 3.82 x 10^5 km = 3.82 x 10^8 m
The gravitational force between earth and moon is
F = G Me x Mm / r^2
F = (6.67 x 10^-11 x 5.98 x 10^24 x 7.36 x 10^22) / (3.82 x 10^8 x 3.82 x 10^8)
F = 2 x 10^20 N
Here's link
to the answer:
bit.ly/3gVQKw3
To solve the problem, use Kepler's 3rd law :
T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
but first covert 6.00 years to seconds :
6.00years = 6.00years(365days/year)(24.0hours/day)(6...
= 1.89 x 10^8s
The radius of the orbit then is :
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓
= 6.23 x 10^11m
