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2 years ago

A body displaces 50cm^3 of water. What is the up-thrust on the body?

Physics

1 answer:

SVEN [57.7K]2 years ago

3 0

Answer:

Force of buoyancy is given by

Fb = Weight of displaced water

= mg

But, m=density x volume

= ρV g

where ρ = density of the water

V = volume of displaced water = volume of block

g = acceleration due to gravity

Given that,

V = 50 cm3

g = 981 cm/s2

ρ = 1 g/cm3

Fb = 1*50*981

= 49050 dyne

= 0.49 N

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7. Mrs. Everhart developed the theory that all bulldogs are great pets. After all her bulldog Meatball is a

Advocard [28]

Answer: No.

Explanation:

A scientific theory is an explanation of some aspect of the natural world that can be tested several times, and follows the scientific method. And, when possible, theories are tested with experiments.

Now, a scientific theory must meet some criteria, and one of those is that it must be supported by several (and independent) strands of evidence.

In this case, we have only one, Meatball, and it is not enough, then it can not be a scientific theory.

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2 years ago

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface. When she lands on Noveria, a distant planet in

Anastasy [175]

Answer:

Acceleration of gravity on Noveria = 4.4 m/s²

Explanation:

Commander Shepard, an N7 spectre for Earth, weighs 799 N on the Earth's surface.

We have weight, W = mg

Acceleration due to gravity, g = 9.81m/s²

799 = m x 9.81

Mass of Shepard, m = 81.45 kg

She lands on Noveria, a distant planet in our galaxy, she weighs 356 N.

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356 = 81.45 xg'

Acceleration of gravity on Noveria, g' = 4.4 m/s²

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3 years ago

Sawyer launches his 180 kg raft on the Mississippi River by pushing on it with a force of 75N. How long must Sawyer push on the

Daniel [21]

Answer: 4.8 s

Explanation:

We have the following data:

$m=180 kg$ the mass of the raft

$F=75 N$ the force applied by Sawyer

$V=2 m/s$ the raft's final speed

$V_{o}=0 m/s$ the raft's initial speed (assuming it starts from rest)

We have to find the time $t$

Well, according to Newton's second law of motion we have:

$F=m.a$ (1)

Where $a$ is the acceleration, which can be expressed as:

$a=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{t-t_{o}}$ (2)

Substituting (2) in (1):

$F=m\frac{V-V_{o}}{t-t_{o}}$ (3)

Where $t_{o}=0$

Isolating $t$ from (3):

$t=\frac{m(V-V_{o})}{F}$ (4)

$t=\frac{180 kg(2 m/s-0 m/s)}{75 N}$

Finally:

$t=4.8 s$

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2 years ago

A turtle takes 3.5 minutes to walk 18 m toward the south along a deserted highway. A truck driver stops and picks up the turtle.

Akimi4 [234]

Answer:

3.59 m/s

Explanation:

The average velocity is defined as:

$\frac{Total displacement}{Total time}$

The turtle first walks 18m south, and then is taken 1,1Km (or 1100m) north. Thus, the total displacement is 1082m north (1100m north - 18m south).

Now we have to calculate the total time, which will be equal to the sum of the time the turtle walked and the time it was taken by truck.

The walking time is 3.5 minutes. Since 1 minute = 60 seconds, then the walking time is 210 seconds.

To calculate the truck time we use the equation:

Time = $\frac{Distance}{Speed}$

Where the distance the truck travelled is 1100m and the speed of the truck is 12m/s.

Thus,

Truck time= $\frac{1100m}{12m/s}$ = 91.67s

The total time is the sum of the walking time and the truck time.

Total time = 210s + 91.67s = 301.67s.

As mencioned previously, the average velocity is equal to total displacement/ total time, thus:

Average velocity = $\frac{1082m}{301.67s}$ = 3.59 m/s North

Since the average velocity is a vector, it has a magnitude and a direction. In this case the magnitude is 3.59 m/s and the direction is north since the turtle's final displacement is north of where it started.

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2 years ago

While running at a constant velocity, how should you throw a ball with respect to you so that you can catch it yourself?

timurjin [86]

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3 years ago

A body displaces 50cm^3 of water. What is the up-thrust on the body? ​

A body displaces 50cm^3 of water. What is the up-thrust on the body?