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UNO [17]
2 years ago
9

Solve the right triangle, AABC, for the missing sides and angle to

Mathematics
1 answer:
jolli1 [7]2 years ago
8 0

Answer:

please see photo for detailed analysis.

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Debbie has $460 in a savings account that earns 8% annually. If the interest is not compounded, how much interest will she earn
vitfil [10]
The answer is C.)
since the 8% of $460 is $36.80 
the next 5 years will increase at the same rate
so then you have to multiply 36.80 by 5 which equals $184
5 0
3 years ago
If the lines px = 12 and 2x + qy = 10 intersects at (1 , 1), what is the value of p + q?
shusha [124]

Answer:

p + q = 20

Step-by-step explanation:

Given the lines intersect at (1, 1 ) then x = 1 and y = 1 make the equations true.

Consider

px = 12 with x = 1

p = 12

Consider

2x + qy with x = 1 and y = 1

2 + q = 10 ( subtract 2 from both sides )

q = 8

Hence p + q = 12 + 8 = 20

5 0
3 years ago
What steps is flip second fraction only?
Assoli18 [71]

Answer:

To multiply two fractions, we multiply the numerators to get the new numerator and multiply the denominators to get the new denominator. However, we are taught that when faced with a problem such as 3⁄5 ÷ 4⁄7, we should invert the second fraction and multiply.

7 0
2 years ago
Multiple all the coordinates by 1/5.
Andrew [12]

Answer:

(-1,2) , (2,-1), (2,-1) , (-2,1)

Step-by-step explanation:

-5 x 0.2=-1

5 x 0.2=1

10 x 0.2= 2

-10x 0.2=-2

6 0
3 years ago
Theorem: The segment joining the midpoints of two sides of a triangle is parallel to the third side and half its length. A two-c
natali 33 [55]

Answer:  By the slope formula.

Step-by-step explanation:

Given: ABC is a triangle (shown below),

In which A≡(6,8), B≡(2,2) and C≡(8,4)

And, D and E are the mid points of the line segments AB and BC respectively.

Prove: DE║AC and DE = AC/2

Proof:

Since, And, D and E are the mid points of the line segments AB and BC respectively.

Therefore, By mid point theorem,

coordinate of D are (\frac{2+6}{2} , \frac{2+8}{2} ) = (\frac{8}{2} , \frac{10}{2} )= (4,5)

Coordinate of E are  (\frac{2+8}{2} , \frac{2+4}{2} ) = (\frac{10}{2} , \frac{6}{2} )= (5,3)

By the distance formula,

DE=\sqrt{(5-4)^2+(3-5)^2}=\sqrt{5}

AC=\sqrt{(8-6)^2+(4-8)^2}=2\sqrt{5}

By the slope formula,

Slope of AC = \frac{4-8}{8-6} = \frac{-4}{2} = -2

Slope of DE =  \frac{3-5}{5-4} = \frac{-2}{1} = -2


            Statement                                              Reason

1. The coordinate of D are (4,5)  and           1. By the midpoint formula

the coordinate of  E are (5,3)

2. The length of DE = √5                            2. By the Distance formula

The length AC = 2√5 ⇒ Segment DE

is half the length of segment AC

3. The slope of DE = -2 and the                3. By the slope formula

slope of AC = -2

4. DE║AC                                                   4. Slopes of parallel lines are equal


7 0
3 years ago
Read 2 more answers
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