Four times d to the third minus ten
Given :




Let's solve by using midpoint formula :










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Answer:
-5 ≤ n ≤ 3
Step-by-step explanation:
Firstly we solve the equation two at a time;
5n + 17 ≥ n - 3
5n - n ≥ -3 - 17
4n ≥ -20
n ≥ -5
-5 ≤ n
n - 3 ≥ -15 + 5n
n - 5n ≥ -15 + 3
-4n ≥ -12
-n ≥ -3
n ≤ 3
Therefore,
5n+17 ≥ n–3 ≥ –15+5n, becomes
-5 ≤ n ≤ 3
Rate of change=(changespeed)/(changetime)=(s1-s2)/(t1-t2)
change is (0-60)/(0-5)=-60/-6=12
answer is 12 units per second