It should b noted that the main things that should be included on the outline for an argument include the introduction, body, and conclusion.
The introductory paragraph outlines the topic and provides background information that is important for the readers to understand the argument.
The body paragraphs explain the reasons that support the thesis. It clearly explains why the reader should agree with the position stated.
Lastly, the conclusion restates the thesis and then summarizes the arguments made.
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1.12 divided by 12 times three. In that order.
Answer:fix:f(56) 67
Step-by-step explanation:(45)x78,]~27
Given a table <span>representing
the probability distribution of the number of times the John Jay wifi
network is slow during a week. We call the random variable x.
Part A:
The total value of p(x) = 1.
Thus, </span><span>
.08 + .17 + .21 + k + .21 + k + .13 = 1
0.8 + 2k = 1
2k = 1 - 0.8 = 0.2
k = 0.2 / 2 = 0.1
Therefore,
the value of k is 0.1Part B:
The expected value of x is given by
Therefore,
the expected value of x is 3.01Part C:
</span><span>The expected value of
is given by
Therefore,
the expected value of is 12.45</span>
Part D:
The variance of x is given by
Therefore,
the variance of x is 3.39.
Part E
<span>The standard deviation of x is given by
Therefore,
the standard deviation of x is 1.84.
Part F:
The variance of ax, where a is a constant is given by
Thus, the variance of 3x is given by
Therefore,
the variance of 3x is 30.51.
Part G:
The probability that the network has no more that 4 slow times in one week is given by
Since, the </span>network slowness is independent from week to week, the <span>probability that if we look at 5 separate weeks, the network has no more than 4 slow times in any of those weeks is given by
Therefore, </span>
the probability that if we look at 5 separate weeks, the network has no more than 4 slow times in any of those weeks is 0.27Part H:
The variance of x^2 is given by
Thus,
Therefore,
the <span>
variance of the random variable is 141.37</span>
Answer:
8% C = 4 1% C = 4 ÷ 8 =0.5 100% C = 0.5 × 100 = 50