All categories

3 years ago

Help please I need this

Mathematics

1 answer:

Sindrei [870]3 years ago

3 0

9514 1404 393

Answer:

Slant Height = 20.1 km
Radius = 9 km
Lateral Area = 568.3 km²

Step-by-step explanation:

The slant height is read from the diagram as 20.1 km.

The radius is half the diameter, so is 9.0 km.

The lateral area is ...

A = πrs = π(9.0 km)(20.1 km) ≈ 568.3 km²

Desmos uses r for a special purpose, so we have used r₁ to signify the radius of the cone. The "round" function works only to round to an integer, so special effort must be used to get rounding to 1 decimal place.

You might be interested in

Write an equation for the line shown pictured in the graph.

avanturin [10]

The answer is y=5+0
3

8 0

3 years ago

Two cylinders are similar. The radius of cylinder a is 5.6 in. The radius of cylinder b is 1.4 in. If the hwight of cylinder b i

sleet_krkn [62]

The answer is 16in.

Let the radius and height of cylinder A be Ra and Hb respectively and the radius and height of cylinder B be Rb and Hb respectively.

Using similar shapes:
Ra/Ha= Rb/Hb
5.6/Ha=1.4/4
Ha=(4×5.6)/1.4
Ha=22.4/1.4
Ha=16in

6 0

3 years ago

If a(x) = 3x + 1 and b(x)= squareroot x-4, what is the domain of (b*a)(x)?

oksano4ka [1.4K]

$\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Further explanation</h3>

This is a question about the composition of functions and how to get a domain function.

Given $\boxed{ \ a(x) = 3x + 1 \ }$ and $\boxed{ \ b(x) = \sqrt{x - 4} \ }$ .

We will form (b o a)(x) and then determine the domain.

$\boxed{ \ (b \circ a)(x) = b(a(x)) \ }$

Replace each appearance of x in b(x) with $\boxed{ \ a(x) = 3x + 1 \ }$ .

$\boxed{ \ (b \circ a)(x) = \sqrt{(3x + 1) - 4} \ }$

Thus, $\boxed{ \ (b \circ a)(x) = \sqrt{3x - 3} \ }$

To be defined, the value under the radical sign must not be negative. Therefore, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ are processed as follows.

$\boxed{ \ 3x - 3 \geq 0 \ }$

Both sides added by 3.

$\boxed{ \ 3x \geq 3 \ }$

Both sides divided by 3.

$\boxed{ \ x\geq 1 \ }$

Thus, the domain of $(b \circ a)(x) = \sqrt{3x - 3}$ is $\boxed{ \ x \geq 1 \ }$ or can be written as $\boxed{ \ [1, \infty) \ }$

<h3>Learn more</h3>

If f(x) = x² – 2x and g(x) = 6x + 4, for which value of x does (f o g)(x) = 0? brainly.com/question/1774827
Solve for the value of the function composition brainly.com/question/2142762
Look for rotation rules in the transformation brainly.com/question/2992432

Keywords: composition of function, if a(x) = 3x + 1, and, b(x) = √(x-4), what is the domain of, (b o a)(x), b(a(x)), defined, the value, under the radical sign, must not be negative,