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Shalnov [3]
3 years ago
7

The address of the Earth in as much detail as possible

Physics
1 answer:
igor_vitrenko [27]3 years ago
8 0
3 Solar System
The Milky Way
The Galaxy
IDK
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What is the impulse needed to stop a 45-kg boy who is running at 6 m/s in 3 seconds?
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Impulse = change of momentum
Impulse = 45 x 6 = 270 Ns
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3 years ago
An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in
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Answer:

<em>-z axis</em>

Explanation:

According to the left hand rule for an electron in a magnetic field, hold the thumb of the left hand at a right angle to the rest of the fingers, and the rest of the fingers parallel to one another. If the thumb represents the motion of the electron, and the other fingers represent the direction of the field, then the palm will push in the direction of the force on the electron. In this case, the left hand will be held out with the thumb pointing to the right (+x axis), and the palm facing your body (-y axis). The magnetic field indicated by the other fingers will point down in the the -z axis.

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3 years ago
X-rays cannot pass through Earth's atmosphere. Which of these is the best location to place a telescope used to observe x-rays f
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Mountains, tops of buildings, and high-flying aircraft are all part of Earth's atmosphere, no matter how high they are. On the other hand, space doesn't belong to our atmosphere, it is outside of it. Having this in mind, the best location to place a telescope used to observe x-rays from stars is in space.
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3 years ago
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A sound that's produced by a single wave at a constant frequency and with no overtones is called
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It is called a pure sound
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Unpolarized light is incident upon two ideal polarizing filters that do not have their transmission axes aligned. If 19% of the
Zepler [3.9K]

Answer:

51.94°

Explanation:

I_0 = Unpolarized light

I_2 = Light after passing though second filter = 0.19I_0

Polarized light passing through first filter

I_1=\frac{I_0}{2}

Polarized light passing through second filter

I_2=\frac{I_0}{2}cos^2\theta\\\Rightarrow 0.19I_0=\frac{I_0}{2}cos^2\theta\\\Rightarrow cos^2\theta=\frac{0.19I_0}{\frac{I_0}{2}}\\\Rightarrow cos\theta=\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{\frac{0.19I_0}{\frac{I_0}{2}}}\\\Rightarrow \theta=cos^{-1}\sqrt{0.19\times 2}\\\Rightarrow \theta=cos^{-1}\sqrt{0.38}\\\Rightarrow \theta=51.94^{\circ}

The angle between the two filters is 51.94°

5 0
3 years ago
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