Take the moment car A starts to accelerate to be the origin. Then car A has position at time <em>t</em>
<em>x</em> = (20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>²
and car B's position is given by
<em>x</em> = 300 m + (27.0 m/s) <em>t</em>
<em />
Car A overtakes car B at the moment their positions are equal:
(20.0 m/s) <em>t</em> + 1/2 (2.10 m/s²) <em>t</em>² = 300 m + (27.0 m/s) <em>t</em>
300 m + (7.00 m/s) <em>t</em> - (1.05 m/s²) <em>t</em>² = 0
==> <em>t</em> ≈ 20.6 s
<span>The most likely type of star to be found in the halo are stars classified as M stars. These stars absorb red light, have temperatures under 3000K, have an average mass of .3 times the mass of the sun, have an average radius of .4 times the radius of the sun, and have .04 times the luminosity of the sun.</span>
Answer:
a) F = 2.25 10³ N, b) REPULSIVE.
Explanation:
a) The electric force is given by coulomb's law
F =
k q1q2 / r2
in this case nso indicate that the two charges have the same value
q₁ = q₂ = 2.5 10⁻⁶ C
Let's reduce the magnitudes to the SI system
r = 0.5 cm (1m / 100cm) = 5 10⁻³ m
let's calculate
F =
F = 2.25 10³ N
b) In electricity, electric charges of the same sign repel and those of the opposite sign attract
In this exercise, the balls are equal and are rubbed with the same material, for which it acquires charges of the same type, consequently, as the charges are of the same type, they indicate that the negative force is REPULSIVE.