Answer:
Amplitude = 4.725 mm
Explanation:
We have got the following values :
T = 98.4 N
T is the wire tension
v = 406 m/s
v is the transverse waves speed
f = 60.5 Hz
f is the frequency
ΔU = 0.391 W
ΔU is the average power carried by the wave
If μ is the mass per unit length of the wire ⇒ μ =
If ω is the angular frequency of the wire ⇒ ω = 2π.f
So ω = 2π(60.5 Hz) and ω units are
The equation that relates all is :
ΔU = (1/2).(T/v^2).(ω^2).(A^2).v
Where A is the wave amplitude
This will give us A in meters
Answer:
Both objects have the same magnitude of momentum.
Explanation:
If an object of mass is moving at a velocity of
, the momentum of that object would be
.
The (
) object is moving at a speed of
. The magnitude of the momentum of this object would be
.
Similarly, the momentum of the (
) object moving at a speed of
would be
.
Hence, the magnitude of momentum is the same for the two objects.