Answer:
a)48300 times
b)P = 821100 kg · m/s
Explanation:
Given that
m = 48300 kg
v= 23 m/s
We know that linear momentum (P) given as
P = m v
P = 48300 x 23 kg · m/s
So we can say that truck momentum is 48300 times its velocity.
Now given that
v= 17 m/s
P = m v
P = 48300 x 17 kg · m/s
P = 821100 kg · m/s
Answer:
<h2>solusion </h2><h2>
Explanation:</h2><h2>the answer in 984 </h2>
tha
use Newton's gravitational law and 2nd law .....
The distance to the water is the same for both ... call it s meters
They both take 1.6 s to reach the water ... so t = 1.6 seconds
They both step off the bridge ... so both have an initial vertical velocity is 0 m/s
Just consider the vertical motion and take DOWN as the positive direction
a = 9.8 m/s²
s = v(i)t + (1/2)at²
s = 0 + (1/2) * 9.8 * 1.6²
s = 12.5 m ←←← Edit: Forgot to say ... that's how high the bridge is above the water
Now get the time it takes the first jumper to reach 1.8 m:
s = v(i)t + (1/2)at²
1.8 = 0 + 4.9t²
t = 0.61 s
so when the 2nd person jumps it takes the first person another 1.6 - 0.61 = 0.99 s to reach the water
Now find how far the 2nd jumper falls in 0.99 s:
s = 0 + 4.9 * 0.99²
s = 4.8 m
so the separation distance between the two jumpers when the 1st jumper hits the water is 12.5 - 4.8 = 7.7 m
Answer:
t=1.87s
b. 9.74
Explanation:
First to find time set an equation for angular velocity:
Now to find the angle:
