We use the Planck’s formula:
E = hv
where,
E = energy, h = planck’s constant = 6.6x10^-34 J s, v =
frequency in Hz (Hz = 1 / s)
Subsituting the values to find for E:
E = (6.6×10^-34 J s) * 9.85×10^14 / s
E = 6.5x10^-19 J
Answer:
The answer is Avogadro's Law.
Explanation:
Avogardo's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules." The derivation of Avogadro's law follows directly from the ideal gas law is:
where
;
V is the volume of the gas;
n is the amount of substance of the gas (measured in moles);
k is a constant for a given temperature and pressure
P is pressure of the environment
T is temperature of the environment
The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.
The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.
Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;
ΔK.E ∝ T
The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.
Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.
Thus, the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.
Learn more about temperature and kinetic energy here: brainly.com/question/305606
Answer:
Explanation:
Let T be the tension in the cord.
Impulse by cord = change in momentum of block A .
T x 5s = 10 ( 2 -0) = 20
T = 4 poundal .
acceleration of block B = 2 / 5 = 0.4 m /s²
Net force applied on A = m ( g + a ) where m is mass of block B , a is acceleration of block B .
= 8 ( 32 + .4 ) = 259.2 poundal
Frictional force on block A = 259.2 - 4 = 255.2 poundal
μ x 10 x 32 = 255.2
320μ = 255.2
μ =0 .8 .
