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vlada-n [284]
1 year ago
13

V=I/R correctly expresses the relationship between voltage, current, and resistance.

Physics
2 answers:
docker41 [41]1 year ago
5 0
The correct answer is true
emmasim [6.3K]1 year ago
4 0

Answer:

False

Explanation:

It is actually I = V/R and V = I × R

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Alex17521 [72]
I would go with Segment D.
5 0
3 years ago
Read 2 more answers
A charged particle A exerts a force of 2.45 μN to the right on charged particle B when the particles are 12.2 mm apart. Particle
Brilliant_brown [7]

Answer:

F_2 = 1.10 \mu N

Explanation:

As we know that the electrostatic force is a based upon inverse square law

so we have

F = \frac{kq_1q_2}{r^2}

now since it depends inverse on the square of the distance so we can say

\frac{F_1}{F_2} = \frac{r_2^2}{r_1^2}

now we know that

r_2 = 18.2 mm

r_1 = 12.2 mm

also we know that

F_1 = 2.45 \mu N

now from above equation we have

F_2 = \frac{r_1^2}{r_2^2} F_1

F_2 = \frac{12.2^2}{18.2^2}(2.45\mu N)

F_2 = 1.10 \mu N

5 0
3 years ago
If skater A is more massive than skater B, how will skater A's motion compare to the motion of skater B?
adell [148]
<span>d) more information is needed in order to figure this out..... I would say because how large someone is would not change the direction of them while skating.</span>
7 0
3 years ago
1. An electric lamp a marked 240V, 6A. What
Annette [7]

Answer:

The resistance of the lamp is 4Ω.

Explanation:

You have to apply voltage formula :

V = I × R

R = V ÷ I

R = 240 ÷ 60

R = 4 Ω

8 0
2 years ago
What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?
Tom [10]

The magnitude of 'g' at a place is expressed in terms of
the acceleration due to gravity.

You have said that the gravitational acceleration at that place
is 6.5 m/s².  So THAT's the magnitude of 'g' right there.

4 0
3 years ago
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